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In the slow start phase of the TCP congestion control algorithm, the size of the congestion window
In the slow start phase of the TCP congestion control algorithm, the size of the congestion window increases exponentially. Specifically, the congestion window size starts at a small value, typically one or two segments, and then doubles every round trip time (RTT), as long as acknowledgments continRead more
In the slow start phase of the TCP congestion control algorithm, the size of the congestion window increases exponentially. Specifically, the congestion window size starts at a small value, typically one or two segments, and then doubles every round trip time (RTT), as long as acknowledgments continue to be received and no packet loss is detected. This exponential growth occurs because for every acknowledgment received, the congestion window size increases by one segment, effectively doubling the window size each RTT. This exponential increase continues until a packet loss is detected or the congestion window size reaches a threshold value, known as the slow start threshold (ssthresh), at which point the congestion control algorithm transitions from the slow start phase to the congestion avoidance phase.
See lessConsider different activities related to email. m1:Send an email from a mail client to mail server m2:Download an email from mailbox server to a mail client m3:Checking email in a web browser Which is the applicable level protocol user in each activity?
For the activities related to email that you've mentioned, the applicable level protocols are as follows:- m1: Sending an email from a mail client to a mail server typically involves the Simple Mail Transfer Protocol (SMTP). SMTP is used for the transmission of emails from the source address to theRead more
For the activities related to email that you’ve mentioned, the applicable level protocols are as follows:
– m1: Sending an email from a mail client to a mail server typically involves the Simple Mail Transfer Protocol (SMTP). SMTP is used for the transmission of emails from the source address to the destination.
– m2: Downloading an email from mailbox server to a mail client can involve the Post Office Protocol version 3 (POP3) or the Internet Message Access Protocol (IMAP). POP3 is used when the mail client connects to the mail server to download emails to the local device, whereas IMAP is used to access and manage emails directly on the mail server, allowing for more versatile handling of emails across multiple devices.
– m3: Checking email in a web browser doesn’t use the traditional email protocols (SMTP, POP3, IMAP) directly from the client side; instead, it involves Hypertext Transfer Protocol (HTTP) or Hypertext Transfer Protocol Secure (HTTPS). These protocols are used for secure communication between the user’s web browser and the web-based email service (webmail server). The behind-the-scenes action of receiving and sending emails through the web interface still utilizes SMTP, POP3/IMAP as relevant, but this is abstracted from the user.
In summary:
– m1: SMTP for sending emails.
– m2: POP3 or IMAP for downloading emails.
– m3: HTTP or HTTPS for checking emails in a web browser.
See lessSending a file from your personal computer's primary memory or disk to another computer is called
Uploading
Uploading
See lessIf a file consisting of 50,000 characters takes 40 seconds to send, then the data rate is __________
The data rate can be calculated using the formula:[ text{Data rate} = frac{text{Total number of characters}}{text{Time in seconds}} ]Given that the total number of characters is 50,000 and the time taken to send these characters is 40 seconds, we can plug these values into our formula:[ text{Data raRead more
The data rate can be calculated using the formula:
[ text{Data rate} = frac{text{Total number of characters}}{text{Time in seconds}} ]
Given that the total number of characters is 50,000 and the time taken to send these characters is 40 seconds, we can plug these values into our formula:
[ text{Data rate} = frac{50,000 , text{characters}}{40 , text{seconds}} ]
[ text{Data rate} = 1,250 , text{characters per second} ]
See lessIf 5 files are transferred from server A to client B in the same session. The number of TCP connection between A and B is
The number of TCP connections between server A and client B for transferring 5 files in the same session would be 1. TCP establishes a connection before transferring data and maintains that connection until the session ends. Assuming these files are transferred sequentially or even concurrently (givRead more
The number of TCP connections between server A and client B for transferring 5 files in the same session would be 1. TCP establishes a connection before transferring data and maintains that connection until the session ends. Assuming these files are transferred sequentially or even concurrently (given the capabilities of modern TCP implementations) in the same session, only a single TCP connection is necessary.
See lessIn a packet switching network, if the message size is 48 bytes and each packet contains a header of 3 bytes. If 24 packets are required to transmit the message, the packet size is ________
In a packet switching network, where the message is 48 bytes and each packet includes a 3-byte header, to calculate the packet size given that 24 packets are required for transmission, we take the following steps: 1. Determine the total amount of data being sent (including headers).2. Find the sizeRead more
In a packet switching network, where the message is 48 bytes and each packet includes a 3-byte header, to calculate the packet size given that 24 packets are required for transmission, we take the following steps:
1. Determine the total amount of data being sent (including headers).
2. Find the size of each packet.
Firstly, it’s important to note that there seems to be a misunderstanding or typo in the question as presented. If the message size is mentioned to be 48 bytes and 24 packets are required, it implies a division of the total data into these packets. However, the description as is suggests an unrealistic scenario regarding typical packet-switched networking practices where 24 packets would convey much more than 48 bytes even with additional header data per packet.
However, proceeding under the assumption we’re trying to work out the packet size given a typical scenario (and interpreting the 48-byte message size as a mistake or miscommunication), here’s how it would generally be approached:
Given:
– Each packet has a 3-byte header.
– 24 packets are required.
Without clear total message size that fits the context, another way to look at this is perhaps you’re asking how to calculate the size of a packet when parts of its structure are known (header versus payload):
– Each packet has some payload plus the 3-byte header.
If you’re looking for the packet size including the header when 24 packets are transmitted, but based on typical networking principles where the
See lessDSL stands for ————————
DSL stands for Digital Subscriber Line.
DSL stands for Digital Subscriber Line.
See lessIf a file consisting of 50,000 characters takes 40 seconds to send, then thedata rate is __________
To calculate the data rate given a file consisting of 50,000 characters takes 40 seconds to send, you use the formula: data rate = total data transmitted / time it takes to send the data.First, it’s important to understand what is meant by "characters" in terms of data size. Usually, in computing, aRead more
To calculate the data rate given a file consisting of 50,000 characters takes 40 seconds to send, you use the formula: data rate = total data transmitted / time it takes to send the data.
First, it’s important to understand what is meant by “characters” in terms of data size. Usually, in computing, a character is considered to be 1 byte, but this can vary depending on the encoding (for example, ASCII uses 1 byte per character, but Unicode characters can use more). For this calculation, we’ll assume 1 character = 1 byte.
Given:
– 50,000 characters = 50,000 bytes
– Transmission time = 40 seconds
The data rate is: 50,000 bytes / 40 seconds = 1,250 bytes per second.
Therefore, the data rate is 1,250 bytes per second.
See less_______ can detect burst error of length less than or equal to degree of thepolynomial and detects burst errors that affect odd number of bits.
Cyclic Redundancy Check (CRC) can detect burst errors of length less than or equal to the degree of the polynomial and detects burst errors that affect an odd number of bits.
Cyclic Redundancy Check (CRC) can detect burst errors of length less than or equal to the degree of the polynomial and detects burst errors that affect an odd number of bits.
See lessWhich routing protocol below is used by exterior routers between the autonomous systems?
The routing protocol used by exterior routers between autonomous systems is BGP (Border Gateway Protocol).
The routing protocol used by exterior routers between autonomous systems is BGP (Border Gateway Protocol).
See less