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jangyasinni
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Asked: 2024-08-18T23:02:33+05:30 In:

A single phase full bridge inverter has RLC load with R = 4 Ω, L = 35 mH and C = 155 μF. The dc input voltage is 230 V and the output frequency is 50 Hz. Find the rms value of the fundamental load current.

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Poll Results

0%a) 28.31 A ( 0 voters )
100%b) 20.02 A ( 1 voter )
0%c) 16.69 A ( 0 voters )
0%d) 26.90 A ( 0 voters )
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    2 Answers

    1. Quearn
      Best Answer
      Quearnist

      To find the rms value of the fundamental load current for a single-phase full bridge inverter with an RLC load, we can follow these steps:

      1. Calculate the output voltage of the inverter (Vm): For a full bridge inverter, the peak output voltage is equal to the DC input voltage. Thus,

      [

      V_m = V_{dc} = 230 , V

      ]

      2. Calculate the angular frequency (ω): The angular frequency for the output frequency (f) is calculated as:

      [

      omega = 2pi f = 2pi times 50 approx 314.16 , text{rad/s}

      ]

      3. Calculate the reactance of the inductor (XL): The reactance (X_L) is calculated as:

      [

      X_L = omega L = 314.16 times 35 times 10^{-3} approx 10.99 , Omega

      ]

      4. Calculate the reactance of the capacitor (XC): The reactance (X_C) is calculated as:

      [

      X_C = frac{1}{omega C} = frac{1}{314.16 times 155 times 10^{-6}} approx 20.43 , Omega

      ]

      5. **Calculate the total impedance (Z

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    2. jangyasinni
      Teacher

      b

      Explanation: Average value of fundamental output voltage = 4Vs/π = 292.85 V

      X

      L = 2 x 3.14 x 50 x 0.035 = 10.99 Ω

      X

      C = 1/(2 x 3.14 x 50 x 155 x 10

      -6

      ) = 20.54 Ω

      Z = 10.345 Ω

      I = V/Z = 28.31

      I(rms) = V/Z√2 = (292.85)/(1.414 x 10.345) = 20.02 A.

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