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jangyasinni
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Asked: 2024-08-18T23:04:27+05:30 In:

A single phase full bridge inverter has RLC load with R = 4 Ω, Xl = 11 Ω and Xc = 20.54 Ω. The dc input voltage is 230 V. Find the value of fundamental load power.

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Poll Results

0%a) 1633 W ( 0 voters )
100%b) 1603 W ( 1 voter )
0%c) 1576 W ( 0 voters )
0%d) none of the mentioned ( 0 voters )
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    2 Answers

    1. Quearn
      Best Answer
      Quearnist

      To find the fundamental load power of a single-phase full bridge inverter with an RLC load, we first need to determine the total impedance (Z) of the load.

      1. Calculate the reactance (X):

      [

      X = X_L – X_C = 11 , Omega – 20.54 , Omega = -9.54 , Omega

      ]

      2. Calculate the total impedance (Z):

      [

      Z = sqrt{R^2 + X^2} = sqrt{4^2 + (-9.54)^2} = sqrt{16 + 91.52} = sqrt{107.52} approx 10.37 , Omega

      ]

      3. Calculate the current (I) using the RMS value of the voltage:

      [

      I = frac{V_{dc}}{Z} = frac{230 , V}{10.37 , Omega} approx 22.17 , A

      ]

      4. Calculate the power factor (pf):

      [

      pf = cos(theta) = frac{R}{Z} = frac{4 , Omega}{10.37 , Omega} approx 0.385

      ]

      5. Calculate the fundamental load power (P):

      [

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    2. jangyasinni
      Teacher

      b

      Explanation: Average value of fundamental output voltage = 4Vs/π = 292.85 V

      Z = [R

      2 + (Xl – Xc)

      2

      ]

      1/2

      I = V/Z = 28.31

      I(rms)(fundamental) = V/Z√2 = (292.85)/(1.414 x 10.345) = 20.02 A

      Fundamental Load power = (20.02)

      2 x R = (20.02)

      2 x 4 = 1603.2 Watts.

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