A single phase full bridge inverter using transistors and diodes is feeding a R load of 3 Ω with the dc input voltage of 60 V. Find the rms output voltage and the peak reverse blocking voltage of each transistor.

To find the RMS output voltage (V_rms) and the peak reverse blocking voltage (V_r) of each transistor in a single-phase full bridge inverter feeding a resistive load (R) of 3 Ω with a DC input voltage (V_dc) of 60 V, we can use the following formulas:

1. RMS Output Voltage (V_rms):

For a full bridge inverter, the RMS output voltage can be calculated using:

[

V_{rms} = frac{V_{dc}}{2}

]

Substituting the given DC input voltage:

[

V_{rms} = frac{60 V}{2} = 30 V

]

2. Peak Reverse Blocking Voltage (V_r):

The peak reverse blocking voltage for each transistor is equal to the DC input voltage since, during the off state, they must block the full DC voltage. Therefore:

[

V_r = V_{dc} = 60 V

]

### Answers:

– RMS Output Voltage (V_rms): 30 V

– Peak Reverse Blocking Voltage (V_r): 60 V