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jangyasinni
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Asked: 2024-08-18T23:33:15+05:30 In:

A single-phase half bridge inverter is connected to a 230 V dc source which is feeding a R load of 10 Ω. Determine the fundamental power delivered to the load.

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0%a) 1.07 W ( 0 voters )
0%b) 107.2 W ( 0 voters )
100%c) 1.07 kW ( 1 voter )
0%d) 107.2 kW ( 0 voters )
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    2 Answers

    1. Quearn
      Best Answer
      Quearnist

      To determine the fundamental power delivered to the load in a single-phase half-bridge inverter connected to a DC source, we can follow these steps:

      1. Determine the RMS Voltage (V_rms) across the load:

      In a half-bridge inverter, the output voltage (V_out) switches between 0 and the DC supply voltage (V_dc). The effective RMS voltage delivered to the load can be calculated as:

      [

      V_{rms} = V_{dc} / 2

      ]

      Given ( V_{dc} = 230 V ):

      [

      V_{rms} = 230 V / 2 = 115 V

      ]

      2. Calculate the Load Current (I_rms):

      Ohm’s Law ((V = IR)) can be used to find the current through the load:

      [

      I_{rms} = V_{rms} / R

      ]

      Where ( R = 10 , Omega ):

      [

      I_{rms} = 115 V / 10 , Omega = 11.5 A

      ]

      3. Calculate the Power (P) delivered to the load:

      The power delivered to the load can be calculated using the formula:

      [

      P = V_{rms} times I_{rms} times cos(phi)

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    2. jangyasinni
      Teacher

      c

      Explanation: The fundamental power is the power delivered to the load due to the

      fundamental components of voltage and current.

      V

      1 (rms) = 2Vs/√2π = 103.552 V

      I

      1 (rms) = V

      1

      /R = 10.3552 A

      P = (I

      1

      )

      2 x R = 1072.3 W = 1.0723 kW

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