Poll Results
No votes. Be the first one to vote.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
To calculate the capacitance of a parallel plate capacitor in air, you can use the formula:
[C = epsilon_r epsilon_0 frac{A}{d}]
Where:
– (C) is the capacitance in farads (F),
– (epsilon_r) is the relative permittivity of the dielectric material between the plates (for air, it can be approximated as 1),
– (epsilon_0) is the vacuum permittivity, equal to approximately (8.854 times 10^{-12} text{F/m}) (farads per meter),
– (A) is the area of one of the plates in square meters (m²),
– (d) is the distance between the plates in meters (m).
Given:
– (A = 20) units (assuming units means square meters, (20 m^2)),
– (d = 5 m),
The equation with given values:
[C = 1 times 8.854 times 10^{-12} text{F/m} times frac{20}{5}]
[C = 8.854 times 10^{-12} text{F/m} times 4]
[C = 35.416 times 10^{-12} text{F}]
[C = 35.416 text{pF}]