Poll Results
No votes. Be the first one to vote.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
b
Explanation: The dipole moment of charge 2C and distance 2cm will be,
M = Q x d. Thus, M = 2 x 0.02 = 0.04 C-m.
The dipole moment ((p)) is calculated using the formula:
[p = q times d]
where (q) is the magnitude of the charge and (d) is the separation distance between the charges.
Given:
– (q = 2C) (Note: In a real-world context, a charge of 2 Coulombs is extremely large for discussions of dipole moments, suggesting this might be a hypothetical question for illustrative purposes.)
– (d = 2cm = 0.02m) (It’s important to convert distance to meters in the SI system for consistency.)
Substituting the given values into the formula:
[p = 2C times 0.02m = 0.04 Ccdot m]
So, the dipole moment of the dipole is (0.04) Coulomb-meter ((Ccdot m)).