jangyasinniTeacher
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
To calculate the displacement current density ((J_d)) when the electric flux density ((D)) is given by (D = 20sin(0.5t)), we’ll make use of Maxwell’s displacement current concept. The displacement current density can be found using the equation:
[
J_d = frac{dD}{dt}
]
Given that (D = 20sin(0.5t)), let’s differentiate it with respect to (t):
[
frac{dD}{dt} = 20cos(0.5t) times 0.5 = 10cos(0.5t)
]
So, the displacement current density, (J_d), is:
[
J_d = 10cos(0.5t)
]
This expression provides the displacement current density as a function of time.
b
Explanation: The displacement current density is given by, Jd = dD/dt.
Jd = d(20sin 0.5t)/dt = 20cos 0.5t (0.5) = 10cos 0.5t.
b) 10cos 0.5t
Explanation: The displacement current density is given by, Jd = dD/dt.
Jd = d(20sin 0.5t)/dt = 20cos 0.5t (0.5) = 10cos 0.5t.