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To calculate the power of a material given an electric field, a distance, and a current, we start by recognizing that the electric field (E) expression in volts per meter (V/m) can be related to the voltage (V) across the material and the distance (d) over which the field is applied. The basic relationship between the electric field and voltage is:
[ E = frac{V}{d} ]
Given that the electric field (E) is 100 units (assuming the units are V/m since the typical unit for electric field intensity is volts per meter), and the distance (d) is 10 cm (which needs to be converted into meters for consistency in SI units, thus 10 cm = 0.1 m), the voltage across the material can be calculated by rearranging the formula to solve for V:
[ V = E times d ]
[ V = 100 times 0.1 = 10 text{ volts} ]
With a current (I) of 2 A flowing through it, the power (P) dissipated by or provided to the material can be calculated using the formula for electrical power:
[ P = V times I ]
[ P = 10 times 2 = 20 text{ watts} ]
Thus, the power of the material with an electric field of 100 units/m at a distance of 10 cm with a current of 2 A flowing through it
Answer: b
Explanation: Power is defined as the product of voltage and current.
P = V X I, where V = E X d. Thus P = E X d X I = 100 X 0.1 X 2 = 20 units