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To compute the power consumed by the material, we can use the formula for power ((P)) in terms of the potential difference ((V)) and current ((I)), which is given by:
[P = V times I]
Here, (V = 20V), but (I) is not directly given. Instead, we have the current density ((J)) and area ((A)), which we can use to find (I), as the current density is defined as the current per unit area (J = frac{I}{A}). Rearranging this for (I) gives us:
[I = J times A]
Given:
– (J = 15) units (assuming the unit is Amperes per square meter, (A/m^2), for current density, which is a common unit),
– (A = 100) units (assuming square meters, (m^2), for area, which matches the unit for current density),
[I = 15 times 100 = 1500 A]
Now, using the formula for power:
[P = 20V times 1500A = 30,000 W]
Therefore, the power consumed by the material is 30,000 Watts or 30 kW.
Answer: c
Explanation: Power is given by, P= V X I, where I = J X A is the current.
Thus power P = V X J X A = 20 X 15 X 100 = 30,000 joule = 30kJ.