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Home/ Questions/Q 1031658
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rohit
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rohitBegginer
Asked: August 27, 20242024-08-27T18:23:03+05:30 2024-08-27T18:23:03+05:30In: Education

Find the angle at which the potential due a dipole is measured, when the distance from one charge is 12cm and that due to other is 11cm, separated to each other by a distance of 2cm.

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100%45 ( 1 voter )
0%60 ( 0 voters )
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    1. Quearn
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      Quearn Quearnist
      2024-08-27T18:23:17+05:30Added an answer on August 27, 2024 at 6:23 pm

      To find the angle at which the potential due to a dipole is measured based on the given distances, we can use the concepts of vectors and geometry applied to electric dipoles. Here, we have a dipole with a separation of 2 cm between the charges, and the points of interest are at distances of 12 cm and 11 cm from the respective charges.

      Given:

      – ( r_1 = 12 ) cm (distance from one charge)

      – ( r_2 = 11 ) cm (distance from the other charge)

      – ( d = 2 ) cm (separation between charges)

      We can solve this by considering the dipole in a coordinate system where the midpoint of the dipole is at the origin and the dipole is aligned along the x-axis. The point where we want to find the potential is at some position ((x, y)) in this coordinate system. However, the key to answering this question lies in finding the angle (theta) that the position vector (from the center of the dipole) makes with the dipole axis (x-axis), which is what is typically referred to when discussing the potential due to a dipole at a certain angle.

      To find (theta), we can use the geometry of the situation. If you draw the scenario, the triangle formed by the distances (r_1), (r_2), and (d) (where (d) is the

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    2. prasanjit
      prasanjit Teacher
      2024-09-21T22:24:24+05:30Added an answer on September 21, 2024 at 10:24 pm

      Answer: d
      Explanation: Here, the two charges are separated by d = 2cm.
      The distance from one charge (say Q1) will be R1 = 11cm. The distance from another

      charge (say Q2) will be R2 = 12cm. If R1 and R2 is assumed to be parallel, then R2 –
      R1 = d cos θ. We get 1 = 2cos θ and cos θ = 0.5. Then θ = cos-1
      (0.5) = 60.

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