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To find the divergence of the vector field (mathbf{F} = x e^{-x} mathbf{i} + y mathbf{j} – xz mathbf{k}), we apply the divergence operator, which is given by:
[
nabla cdot mathbf{F} = frac{partial F_1}{partial x} + frac{partial F_2}{partial y} + frac{partial F_3}{partial z}
]
where (mathbf{F} = F_1 mathbf{i} + F_2 mathbf{j} + F_3 mathbf{k}).
1. Identify the components:
– (F_1 = x e^{-x})
– (F_2 = y)
– (F_3 = -xz)
2. Calculate each partial derivative:
– (frac{partial F_1}{partial x} = frac{partial}{partial x}(x e^{-x}) = e^{-x} – x e^{-x} = (1 – x)e^{-x})
– (frac{partial F_2}{partial y} = frac{partial}{partial y}(y) = 1)
– (frac{partial F_3}{partial z} = frac{partial}{partial z}(-xz) = -x)
3
Answer: a
Explanation: Div(F) = Dx(xe-x) + Dy(y)+Dz(-xz) = -xe-x + e-x + 1 – x =
e-x (1 – x) + (1 – x) = (1 – x)(1 + e-x).