Find the electric potential for an electric field 3units at a distance of 2m.

To find the electric potential given the electric field and distance, we can use the relationship between electric field (E) and electric potential (V), knowing that electric field is the negative gradient of the electric potential. In a uniform electric field, this simplifies to a linear relationship, where the change in electric potential (∆V) equals the electric field (E) times the distance (∆d). Assuming the potential at the starting point is zero, the formula is:

[ Delta V = E times Delta d ]

Given:

– Electric field (E) = 3 units (assuming SI units, this would be 3 N/C)

– Distance (∆d) = 2 m

Substitute the given values into the formula:

[ Delta V = 3 , text{N/C} times 2 , text{m} = 6 , text{V} ]

So, the electric potential difference is 6 volts.

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