Poll Results
No votes. Be the first one to vote.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
No votes. Be the first one to vote.
To find the force between two charges, we can use Coulomb’s Law, which is expressed as:
[F = k cdot frac{|q_1 cdot q_2|}{r^2}]
where:
– (F) is the force between the charges,
– (k) is Coulomb’s constant ((8.987 times 10^9 N m^2/C^2)),
– (q_1) and (q_2) are the magnitudes of the two charges (in this case, 2nC and -1nC, which are (2 times 10^{-9}C) and (-1 times 10^{-9}C) respectively),
– and (r) is the distance between the charges (4cm, which needs to be converted to meters, so (r = 0.04 m)).
Substituting the given values:
[F = 8.987 times 10^9 N m^2/C^2 cdot frac{(2 times 10^{-9} C) cdot (1 times 10^{-9} C)}{(0.04 m)^2}]
[F = 8.987 times 10^9 cdot frac{2 times 10^{-18}}{0.0016}]
[F = 8.987 times 10^9 cdot 1.
c
Explanation: Before the charges are brought into contact, F = 11.234 μN.
After charges are brought into contact and then separated, charge on each sphere is,
(q1 + q2)/2 = 0.5nC
On calculating the force with q1 = q2 = 0.5nC, F = 1.404μN