Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N,

To find the force of interaction between two point charges in a medium, we can use Coulomb’s Law in the form:

[

F = frac{1}{4 pi epsilon} cdot frac{|q_1 q_2|}{r^2}

]

where:

– ( F ) is the force between the charges,

– ( epsilon ) is the permittivity of the medium,

– ( q_1 ) and ( q_2 ) are the magnitudes of the charges,

– ( r ) is the distance between the charges.

In this case, stat coulombs need to be converted to SI units for practical calculation. The conversion is:

1 stat coulomb = ( 3.33564 times 10^{-10} ) C.

So:

– ( q_1 = 60 text{ stat coulombs} = 60 times 3.33564 times 10^{-10} ) C,

– ( q_2 = 37.5 text{ stat coulombs} = 37.5 times 3.33564 times 10^{-10} ) C.

The distance is given as 7.5 cm, which is:

[

r = 7.5 text{ cm} = 0.075 text{ m}

]

Next, to find the permittivity ( epsilon ) for the