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Home/ Questions/Q 1043127
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junaid ansari
Asked: October 8, 20242024-10-08T22:35:33+05:30 2024-10-08T22:35:33+05:30In: Education

Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N

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      Quearn Quearnist
      2024-10-08T22:35:45+05:30Added an answer on October 8, 2024 at 10:35 pm

      To calculate the force of interaction between two charges in a medium other than vacuum, we can use Coulomb’s Law, modified to account for the dielectric constant of the medium ((epsilon_r)).

      The formula for the force between two point charges in a vacuum is given by Coulomb’s law as:

      [

      F = k frac{{|q_1 q_2|}}{{r^2}}

      ]

      where

      – (F) is the force between the charges,

      – (q_1) and (q_2) are the magnitudes of the two charges,

      – (r) is the distance between the charges, and

      – (k) is Coulomb’s constant. For calculations in the cgs system (centimeter, gram, second), specifically for charges measured in statcoulombs, (k) is set to 1 in the appropriate units, which simplifies the equation to:

      [

      F = frac{{|q_1 q_2|}}{{r^2}}

      ]

      When considering a medium with a dielectric constant (epsilon_r), the force is reduced compared to the force in a vacuum. The modified Coulomb’s law takes the dielectric constant into account:

      [

      F = frac{{1}}{{4 pi epsilon_0 epsilon_r}} frac{{|q_1 q_2|}}{{r^2}}

      ]

      In the cgs system, (4 pi

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    2. junaid ansari
      junaid ansari
      2024-10-08T22:36:19+05:30Added an answer on October 8, 2024 at 10:36 pm

      d
      Explanation: 1 stat coulomb = 1/(3 X 109
      ) C
      F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2
      )
      2
      ) = 1.815 X 10-4 N

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