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To find the Laplace equation value of the potential field ( V = x^2 – y^2 + z^2 ), we need to compute the Laplacian operator ( nabla^2 V ) in three-dimensional Cartesian coordinates.
The Laplacian in Cartesian coordinates is given by:
[
nabla^2 V = frac{partial^2 V}{partial x^2} + frac{partial^2 V}{partial y^2} + frac{partial^2 V}{partial z^2}
]
Now, we compute the second derivatives of ( V ):
1. First Partial Derivative with respect to ( x ):
[
frac{partial V}{partial x} = 2x
]
Second Partial Derivative with respect to ( x ):
[
frac{partial^2 V}{partial x^2} = 2
]
2. First Partial Derivative with respect to ( y ):
[
frac{partial V}{partial y} = -2y
]
Second Partial Derivative with respect to ( y ):
[
frac{partial^2 V}{partial y^2} = -2
]
3. First Partial Derivative with respect to ( z ):
[
Answer: b
Explanation: (Del) V = 2x – 2y + 2z
(Del)2 V = 2 – 2 + 2= 2, which is non zero value. Thus it doesn’t satisfy Laplace
equation