Find the potential at a point (4, 3, -6) for the function V = 2x2y + 5z.

To find the potential at a point (4, 3, -6) for the function (V = 2x^2y + 5z), we substitute (x = 4), (y = 3), and (z = -6) into the function:

[V = 2(4)^2(3) + 5(-6)]

First, calculate the square of 4:

[4^2 = 16]

Then multiply the result by 2 and 3:

[2 times 16 times 3 = 96]

Lastly, multiply 5 by -6 and add it to the previous result:

[5 times (-6) = -30]

Adding the two parts together gives:

[96 – 30 = 66]

Therefore, the potential at the point (4, 3, -6) is 66.