In a packet switching network, if the message size is 48 bytes and eachpacket contains a header of 3 bytes. If 24 packets are required to transmit the message, the packet size is .

To calculate the packet size in a packet switching network, we need to consider both the size of the data and the size of the header in each packet. Given that each packet contains a header of 3 bytes and that 24 packets are required to transmit the entire message, we can calculate the packet size as follows:

Let’s denote:

– (H) as the header size per packet,

– (N) as the total number of packets,

– (D) as the data size per packet,

– (T) as the total message size,

– (P) as the packet size (which includes both the header and the data).

From the provided information:

– (H = 3) bytes (header size),

– (N = 24) (number of packets),

– (T = 48) bytes (total message size).

The total size of the message is given, but it seems there might be a confusion in the question as it presents the message size being less than what would be expected given the number of packets and the header size.

However, based on the usual way to find the packet size:

– (P = D + H), where (D) must be calculated or clarified.

For the calculation or approach mentioned in the question (assuming the total message size as transmitted data without headers), the total data that can be transmitted (excluding headers) is:

– Total transmitted data ((T)) minus the total size of all headers ((