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To find the electric potential ( V ) at the origin due to multiple point charges, we use the formula for the electric potential due to a single charge:
[
V = k frac{Q}{r}
]
where ( V ) is the electric potential, ( k ) is Coulomb’s constant (( k approx 8.99 times 10^9 , text{N m}^2/text{C}^2 )), ( Q ) is the charge, and ( r ) is the distance from the charge to the point where the potential is being calculated (in this case, the origin).
For six equal point charges each of ( Q = 10 , text{nC} = 10 times 10^{-9} , text{C} ) located at distances of 2 m, 3 m, 4 m, 5 m, 6 m, and 7 m from the origin, we calculate the potential at the origin due to each charge and then sum them up.
Calculating the potential contributions from each charge:
1. From charge at ( 2 , text{m} ):
[
V_2 = k frac{10 times 10^{-9}}{2} = 8.99 times 10^9 frac{10 times 10^{-9}}{2} = 44
Answer: d
Explanation: V = (1/4πεo) ∑Q/r = (10 X 10-9/4πεo)
(0.5 + 0.33 + 0.25 + 0.2 + 0.166 + 0.142) = 143.35 volts.