The average gate power dissipation for an SCR is 0.5 Watts the voltage applied to the gate is Vg = 10 V. What is the maximum value of current Ig for safe operation

To find the maximum value of the gate current ( I_g ) for safe operation of the SCR given the power dissipation and the voltage applied to the gate, we can use the formula for power:

[

P = V_g cdot I_g

]

Where:

– ( P ) is the power (0.5 Watts),

– ( V_g ) is the voltage applied to the gate (10 V),

– ( I_g ) is the current through the gate.

We can rearrange this formula to solve for ( I_g ):

[

I_g = frac{P}{V_g}

]

Substituting the given values:

[

I_g = frac{0.5 , text{W}}{10 , text{V}} = 0.05 , text{A}

]

Therefore, the maximum value of the gate current ( I_g ) for safe operation is 0.05 A or 50 mA.