Poll Results
No votes. Be the first one to vote.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The conductivity ((sigma)) of a material can be calculated using the formula (sigma = J / E), where (J) is the current density and (E) is the electric field strength.
Given that:
– (J = 1) unit (assuming this is in A/m(^2) since current density is typically measured in Amperes per square meter)
– (E = 200) μV/m (since electric fields are typically measured in volts per meter, and (1) μV = (1 times 10^{-6}) V)
First, convert (E) to V/m for consistency: (200) μV = (200 times 10^{-6}) V/m
Now, we can calculate the conductivity:
[
sigma = frac{J}{E} = frac{1}{200 times 10^{-6}} = frac{1}{0.0002} = 5000 , text{S/m}
]
So, the conductivity of the material is (5000) Siemens per meter (S/m).
d
Explanation: The current density is given by, J = σE. To find conductivity, σ = J/E =
1/200 X 10-6 = 5000.