The gate-source voltage is Es = 16 V and the load line has a slope of 128 V/A. Calculate the gate current for an average gate power dissipation of 0.5 W.

To calculate the gate current (Ig) given the average gate power dissipation (Pg) and the gate-source voltage (Es), we can use the formula for power:

[

P_g = E_s cdot I_g

]

Where:

– ( P_g ) = average power dissipation (in watts)

– ( E_s ) = gate-source voltage (in volts)

– ( I_g ) = gate current (in amperes)

Given:

– ( P_g = 0.5 ) W

– ( E_s = 16 ) V

We can rearrange the formula to solve for the gate current ( I_g ):

[

I_g = frac{P_g}{E_s}

]

Substituting in the given values:

[

I_g = frac{0.5 , text{W}}{16 , text{V}}

]

Calculating this gives:

[

I_g = 0.03125 , text{A} = 31.25 , text{mA}

]

Thus, the gate current is approximately 31.25 mA.