What is the electric field intensity at a distance of 20cm from a charge 2 X 10-6 C in vacuum?

To calculate the electric field intensity (E) at a distance (r) from a point charge (Q) in vacuum, we use the formula:

[ E = frac{k cdot |Q|}{r^2} ]

where:

– ( E ) is the electric field intensity,

– ( k ) is Coulomb’s constant, approximately ( 8.99 times 10^9 , text{N m}^2/text{C}^2 ),

– ( |Q| ) is the magnitude of the charge, and

– ( r ) is the distance from the charge.

Given:

– ( Q = 2 times 10^{-6} ) C,

– ( r = 20 ) cm = ( 0.2 ) m.

Now, substituting the values into the formula:

[ E = frac{8.99 times 10^9 , text{N m}^2/text{C}^2 cdot 2 times 10^{-6} , text{C}}{(0.2 , text{m})^2} ]

Calculating the denominator:

[(0.2)^2 = 0.04 , text{m}^2]

Now substituting back:

[ E = frac{8.99 times 10^9 cdot