Poll Results
No votes. Be the first one to vote.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
No votes. Be the first one to vote.
The efficiency of a Stop and Wait (SAW) protocol is given by the formula:
[ text{Efficiency} = frac{T_t}{T_t + 2 times T_p} ]
Where:
– (T_t) = Transmission time
– (T_p) = Propagation time
Given:
– Transmission time ((T_t)) = 20 ns
– Propagation time ((T_p)) = 30 ns
Plugging the values into the formula:
[ text{Efficiency} = frac{20}{20 + 2 times 30} ]
[ text{Efficiency} = frac{20}{20 + 60} ]
[ text{Efficiency} = frac{20}{80} ]
[ text{Efficiency} = 0.25 ] or 25%
Hence, the efficiency of the Stop and Wait protocol given the conditions is 25%.