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A certain full bridge type inverter circuit has its rms value of fundamental load current component given by W. The fundamental frequency component of the load current would be given by
c Explanation: The fundamental frequency component of the load current is given by Im sin ωt As W = Irms . . . (Given) Im = √2 Irms = √2 W.
c
Explanation: The fundamental frequency component of the load current is given by Im
sin ωt
As W = Irms . . . (Given)
Im = √2 Irms = √2 W.
See lessA single phase full bridge inverter has load R = 2 Ω, and dc voltage source Vs = 230 V. Find the rms value of the fundamental load current.
c Explanation: The fundamental component of voltage = (4Vs/π) sinωt. Peak value Vm = 4Vs/π Rms voltage = 4Vs/π√2 = 207 V Current = 207/2 = 103.5 A.
c
Explanation: The fundamental component of voltage = (4Vs/π) sinωt.
Peak value Vm = 4Vs/π
Rms voltage = 4Vs/π√2 = 207 V
Current = 207/2 = 103.5 A.
See lessA single phase full bridge inverter has a dc voltage source Vs = 230 V. Find the rms value of the fundamental component of output voltage.
b Explanation: The fundamental component of voltage = (4Vs/π) sinωt. Peak value Vm = 4Vs/π Rms value = 4Vs/π√2.
b
Explanation: The fundamental component of voltage = (4Vs/π) sinωt.
Peak value Vm = 4Vs/π
Rms value = 4Vs/π√2.
See lessA single phase half bridge inverter has load R = 2 Ω and a dc voltage source Vs/2 = 115 V. Find the power delivered to the load due to the fundamental component.
c Explanation: Peak value Vm = 2Vs/π Rms value = 2Vs/π√2 = 103.552 V Io = Vo/R = 103.552/2 = 51.776 A P = Io 2 x R = 5361.5 Watts
c
Explanation: Peak value Vm = 2Vs/π
Rms value = 2Vs/π√2 = 103.552 V
Io = Vo/R = 103.552/2 = 51.776 A
P = Io
2 x R = 5361.5 Watts
See lessA single phase half bridge inverter has load R = 2 Ω and a dc voltage source Vs/2 = 115 V. Find the rms value of the fundamental load current.
b Explanation: Peak value Vm = 2Vs/π Rms value = 2Vs/π√2 = 103.552 V Io = Vo/R = 103.552/2 = 51.776 A.
b
Explanation: Peak value Vm = 2Vs/π
Rms value = 2Vs/π√2 = 103.552 V
Io = Vo/R = 103.552/2 = 51.776 A.
See lessA single phase half bridge inverter has a dc voltage source Vs/2 = 115 V. Find the rms value of the fundamental component of output voltage.
b Explanation: The fundamental component of voltage = (2Vs/π) sinωt. Peak value Vm = 2Vs/π Rms value = 2Vs/π√2 = 103.552 V.
b
Explanation: The fundamental component of voltage = (2Vs/π) sinωt.
Peak value Vm = 2Vs/π
Rms value = 2Vs/π√2 = 103.552 V.
See lessFor a half wave bridge inverter, the output voltage
b Explanation: In case of a half wave inverter, for the first half cycle, Vo = Vs/2 and for the second half cycle Vo = -Vs/2.
b
Explanation: In case of a half wave inverter, for the first half cycle, Vo = Vs/2 and for the
second half cycle Vo = -Vs/2.
See lessFor a full wave bridge inverter, the output voltage (Vo)
b Explanation: For the first half cycle, Vo = Vs and for the second half cycle Vo = -Vs
b
Explanation: For the first half cycle, Vo = Vs and for the second half cycle Vo = -Vs
See lessIn the following circuit, the diodes D1 to D4 are used to
b Explanation: Diodes are connected in anti-parallel with the SCRs during inductive loads for freewheeling actions.
b
Explanation: Diodes are connected in anti-parallel with the SCRs during inductive loads
for freewheeling actions.
See lessIn a single phase full wave bridge inverter, when the output is Vs or –Vs
c Explanation: When two SCRs are conducting, T1-T2 or T3-T4, the output voltage magnitude is Vs. When the diodes are conducting, freewheeling action is taking place and voltage is zero.
c
Explanation: When two SCRs are conducting, T1-T2 or T3-T4, the output voltage
magnitude is Vs. When the diodes are conducting, freewheeling action is taking place
and voltage is zero.
See less