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jangyasinni

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  1. Asked: August 28, 2024In: Education

    If the loss tangent is very less, then the material will be a

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:20 pm

    b Explanation: If loss tangent is less, then σ /ε ω <<1. This implies the conductivity is very poor and the material should be a dielectric. Since it is specifically mentioned very less, assuming the conductivity to be zero, the dielectric will be lossless (ideal)

    b

    Explanation: If loss tangent is less, then σ /ε ω <<1. This implies the conductivity is very

    poor and the material should be a dielectric. Since it is specifically mentioned very less,

    assuming the conductivity to be zero, the dielectric will be lossless (ideal)

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      • 0
  2. Asked: August 28, 2024In: Education

    The ratio of conduction to displacement current density is referred to as

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:09 pm

    c Explanation: Jc /Jd is a standard ratio, which is referred to as loss tangent given by σ /ε ω. The loss tangent is used to determine if the material is a conductor or dielectric.

    c

    Explanation: Jc /Jd is a standard ratio, which is referred to as loss tangent given by σ /ε

    ω. The loss tangent is used to determine if the material is a conductor or dielectric.

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      • 0
  3. Asked: August 28, 2024In: Education

    Calculate the frequency at which the conduction and displacement currents become equal with unity conductivity in a material of permittivity 2.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:08 pm

    b Explanation: When Jd = Jc , we get εωE = σE. Thus εo(2∏f) = σ. On substituting conductivity as one and permittivity as 2, we get f = 9GHz

    b

    Explanation: When Jd = Jc , we get εωE = σE. Thus εo(2∏f) = σ. On substituting

    conductivity as one and permittivity as 2, we get f = 9GHz

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      • 0
  4. Asked: August 28, 2024In: Education

    Find the magnitude of the displacement current density in air at a frequency of 18GHz in frequency domain. Take electric field E as 4 units.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:05 pm

    d Explanation: Jd = dD/dt = εdE/dt in time domain. For frequency domain, convert using Fourier transform, Jd = εjωE. The magnitude of Jd = εωE = ε(2πf)E. On substituting, we get 4 ampere.

    d

    Explanation: Jd = dD/dt = εdE/dt in time domain. For frequency domain, convert using

    Fourier transform, Jd = εjωE. The magnitude of

    Jd = εωE = ε(2πf)E. On substituting, we get 4 ampere.

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      • 0
  5. Asked: August 28, 2024In: Education

    Calculate the displacement current density when the electric flux density is 20sin 0.5t.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:04 pm

    b Explanation: The displacement current density is given by, Jd = dD/dt. Jd = d(20sin 0.5t)/dt = 20cos 0.5t (0.5) = 10cos 0.5t.

    b

    Explanation: The displacement current density is given by, Jd = dD/dt.

    Jd = d(20sin 0.5t)/dt = 20cos 0.5t (0.5) = 10cos 0.5t.

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      • 0
  6. Asked: August 28, 2024In: Education

    Find the conductivity of a material with conduction current density 100 units and electric field of 4 units.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:02 pm

    a Explanation: The conduction current density is given by, Jc = σE. To get conductivity, σ = J/E = 100/4 = 25 units.

    a

    Explanation: The conduction current density is given by, Jc = σE. To get conductivity, σ

    = J/E = 100/4 = 25 units.

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      • 0
  7. Asked: August 28, 2024In: Education

    Find the velocity of an electron when its kinetic energy is equal to one electron volt (in 10 5 m/s). Given charge of an electron e = 1.6 x 10 -19 and mass of an electron m = 9.1 x 10

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:01 pm

    c Explanation: When the kinetic energy and one electron volt are equal, we can equate mv 2 /2 = eV. Put e and m in the equation to get velocity v = 5.9 x 10 5 m/s

    c

    Explanation: When the kinetic energy and one electron volt are equal, we can equate

    mv

    2

    /2 = eV. Put e and m in the equation to get velocity v = 5.9 x 10

    5 m/s

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      • 0
  8. Asked: August 28, 2024In: Education

    Find the mean free path of an electron travelling at a speed of 18m/s in 2 seconds.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 8:00 pm

    b Explanation: The mean free path is defined as the average distance travelled by an electron before collision takes place. It is given by, d = v x τc, where v is the velocity and τc is the collision time. Thus d = 18 x 2 = 36m.

    b

    Explanation: The mean free path is defined as the average distance travelled by an

    electron before collision takes place. It is given by, d = v x τc, where v is the velocity and

    τc is the collision time. Thus d = 18 x 2 = 36m.

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      • 0
  9. Asked: August 28, 2024In: Education

    The superconducting materials will be independent of which of the following?

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 7:58 pm

    b Explanation: Superconducting materials depends only on the applied magnetic field, resultant magnetization at the temperature considered. It is independent of the applied electric field and the corresponding polarization.

    b

    Explanation: Superconducting materials depends only on the applied magnetic field,

    resultant magnetization at the temperature considered. It is independent of the applied

    electric field and the corresponding polarization.

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      • 0
  10. Asked: August 28, 2024In: Education

    The magnetic susceptibility in a superconductor will be

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 7:57 pm

    b Explanation: Due to perfect diamagnetism in a superconductor, its magnetic susceptibility will be negative. This phenomenon is called Meissner effect.

    b

    Explanation: Due to perfect diamagnetism in a superconductor, its magnetic

    susceptibility will be negative. This phenomenon is called Meissner effect.

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      • 0
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