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Identify the polarisation of the wave given, Ex = Exo cos wt and Ey = Eyo sin wt. The phase difference is +900 .
c Explanation: The magnitude of the Ex and Ey components are not same. Thus it is elliptical polarisation. For +90 phase difference, the polarisation is left handed. In other words, the rotation is in clockwise direction. Thus the polarisation is left hand elliptical.
c
See lessExplanation: The magnitude of the Ex and Ey components are not same. Thus it is
elliptical polarisation. For +90 phase difference, the polarisation is left handed. In other
words, the rotation is in clockwise direction. Thus the polarisation is left hand elliptical.
When the Ex and Ey components of a wave are not same, the polarisation will be
b Explanation: In elliptical polarisation, the magnitude of Ex and Ey components are not same. This is due to the variation in the major and minor axes of the waves representing its magnitude.
b
See lessExplanation: In elliptical polarisation, the magnitude of Ex and Ey components are not same. This is due to the variation in the major and minor axes of the waves representing its magnitude.
The magnitude of the Ex and Ey components are same in which type of polarisation?
b Explanation: In circular polarisation, the magnitude of the Ex and Ey components are the same. This is a form of the elliptical polarisation in which the major and minor axis are the same.
b
See lessExplanation: In circular polarisation, the magnitude of the Ex and Ey components are the same. This is a form of the elliptical polarisation in which the major and minor axis are the same.
When the phase angle between the Ex and Ey component is 00 or 1800 , the polarisation is
c Explanation: The phase angle between the Ex and Ey component is 00 and 1800 for linearly polarised wave. The wave is assumed to be propagating in the z direction.
c
See lessExplanation: The phase angle between the Ex and Ey component is 00 and 1800
for linearly polarised wave. The wave is assumed to be propagating in the z direction.
For a critical angle of 60 degree and the refractive index of the first medium is 1.732, the refractive index of the second medium is
b Explanation: From the definition of Snell law, sin θc = n2/n1. To get n2, put n1 = 1.732 and θc = 60. Thus we get sin 60 = n2/1.732 and n2 = 1.5.
b
See lessExplanation: From the definition of Snell law, sin θc = n2/n1. To get n2, put n1 = 1.732 and θc = 60. Thus we get sin 60 = n2/1.732 and n2 = 1.5.
The angle at which the wave must be transmitted in air media if the angle of reflection is 45 degree is
a Explanation: In air media, n1 = n2 = 1. Thus, sin θi=sin θt and the angle of incidence and the angle of reflection are same. Given that the reflection angle is 45, thus the angle of incidence is also 45 degree.
a
See lessExplanation: In air media, n1 = n2 = 1. Thus, sin θi=sin θt and the angle of incidence and the angle of reflection are same. Given that the reflection angle is 45, thus the angle of incidence is also 45 degree.
The angle of incidence is equal to the angle of reflection for perfect reflection. State True/False.
a) True
a) True
See lessThe critical angle for two media of refractive indices of medium 1 and 2 given by 2 and 1 respectively is
b Explanation: The sine of the critical angle is the ratio of refractive index of medium 2 to that in medium 1. Thus sin θc = n2/n1. To get θc, put n1 = 2 and n2 = 1. Thus we get θc = sin-1 (n2/n1) = sin-1 (1/2) = 30 degree.
b
See lessExplanation: The sine of the critical angle is the ratio of refractive index of medium 2 to that in medium 1. Thus sin θc = n2/n1. To get θc, put n1 = 2 and n2 = 1. Thus we get θc = sin-1 (n2/n1) = sin-1 (1/2) = 30 degree.
The critical angle is defined as the angle of incidence at which the total internal reflection starts to occur. State True/False.
a Explanation: The critical angle is the minimum angle of incidence which is required for the total internal reflection to occur. This is the angle that relates the refractive index with the angle of reflection in an oblique incidence medium.
a
See lessExplanation: The critical angle is the minimum angle of incidence which is required for the total internal reflection to occur. This is the angle that relates the refractive index with the angle of reflection in an oblique incidence medium.
The refractive index of a medium with permittivity of 2 and permeability of 3 is given by
b Explanation: The refractive index is given by n = c √(με), where c is the speed of light. Given that relative permittivity and relative permeability are 2 and 3 respectively. Thus n= 3 x 108 √(2 x 4π x 10-7 x 3 x 8.854 x 10-12) = 2.45.
b
See lessExplanation: The refractive index is given by n = c √(με), where c is the speed of light.
Given that relative permittivity and relative permeability are 2 and 3 respectively. Thus n= 3 x 108 √(2 x 4π x 10-7 x 3 x 8.854 x 10-12) = 2.45.