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Find the ratio of the refractive index of medium 1 to that of medium 2, when the incident and reflected angles are given by 300 and 450 respectively.
c Explanation: The Snell law is given by N1 sin θi = N2 sin θt. For getting N1/N2, the ratio is sin θt/sin θi. On substituting for θi = 30 and θt = 45, we get sin 45/sin 30 = 2.
c
See lessExplanation: The Snell law is given by N1 sin θi = N2 sin θt. For getting N1/N2, the ratio is sin θt/sin θi. On substituting for θi = 30 and θt = 45, we get sin 45/sin 30 = 2.
The Snell’s law is given by
a Explanation: The Snell law states that in an oblique medium, the product of the refractive index and sine of incidence angle in medium 1 is same as that of medium 2. Thus it is given by N1 sin θi = N2 sin θt.
a
See lessExplanation: The Snell law states that in an oblique medium, the product of the refractive
index and sine of incidence angle in medium 1 is same as that of medium 2. Thus it is
given by N1 sin θi = N2 sin θt.
The Snell’s law can be derived from which type of incidence?
d Explanation: The oblique incidence refers to the interface between dielectric media. Consider a planar interface between two dielectric media. A plane wave is incident at an angle from medium 1 and reflected from medium 2. The interface plane defines the boundary between the media. This is the oblRead more
d
See lessExplanation: The oblique incidence refers to the interface between dielectric media.
Consider a planar interface between two dielectric media. A plane wave is incident at an angle from medium 1 and reflected from medium 2. The interface plane defines the
boundary between the media. This is the oblique medium.
The Brewster angle is the angle of
a Explanation: The Brewster angle is the angle of incidence at which complete transmission of the electromagnetic wave occurs.
a
See lessExplanation: The Brewster angle is the angle of incidence at which complete
transmission of the electromagnetic wave occurs.
Find the ratio of refractive index of medium 2 to that of medium 1, when the Brewster angle is 60 degree.
d Explanation: The tangent of the Brewster angle is the ratio of the medium 2 permittivity to the medium 1 permittivity. Thus tan θb = (n2/n1). Given that θb = 60 degree, the ratio n2/n1 will be tan 60 = 1.732.
d
See lessExplanation: The tangent of the Brewster angle is the ratio of the medium 2 permittivity to the medium 1 permittivity. Thus tan θb = (n2/n1). Given that θb = 60 degree, the ratio n2/n1 will be tan 60 = 1.732.
Find the Brewster angle of a wave transmitted from a medium of permittivity 4 to a medium of permittivity 2.
a Explanation: The Brewster angle is given by θb = tan-1(n2/n1), where n = √ε. Thus wecan express the formula in terms of permittivity as θb = tan-1√ (ε 2/ε 1). Here ε1 = 4 and ε2 = 2. Thus we get θb = tan-1√ (2/4) = tan-1 (0.707) = 35.26 degree.
a
See lessExplanation: The Brewster angle is given by θb = tan-1(n2/n1), where n = √ε. Thus wecan express the formula in terms of permittivity as θb = tan-1√ (ε 2/ε 1). Here ε1 = 4 and ε2 = 2. Thus we get θb = tan-1√ (2/4) = tan-1 (0.707) = 35.26 degree.
An elliptically polarised wave transmitted at the Brewster angle will be received as an elliptically polarised wave. State True/False
b Explanation: Any polarised wave transmitted at the Brewster angle will be linearly polarised. It can be a parallel, perpendicular, circular or elliptical polarisation. The resultant wave is always linearly polarised. This is the reason why the Brewster angle is called polarisation angle.
b
See lessExplanation: Any polarised wave transmitted at the Brewster angle will be linearly
polarised. It can be a parallel, perpendicular, circular or elliptical polarisation. The
resultant wave is always linearly polarised. This is the reason why the Brewster angle is called polarisation angle.
A circularly polarised wave transmitted at the Brewster angle will be received as linearly polarised wave. State True/False
a Explanation: The Brewster angle is said to be the polarisation angle. When a circularly polarised wave is incident at the Brewster angle, the resultant wave will be linearly polarised.
a
See lessExplanation: The Brewster angle is said to be the polarisation angle. When a circularly
polarised wave is incident at the Brewster angle, the resultant wave will be linearly
polarised.
The transmission coefficient of a wave propagating in the Brewster angle is
b Explanation: The transmission coefficient is the reverse of the reflection coefficient. At Brewster angle, the reflection will be zero. Thus the transmission is T = 1-R. Since R = 0, T = 1. It is to be noted that T and R lies in the range of 0 to 1.
b
See lessExplanation: The transmission coefficient is the reverse of the reflection coefficient. At Brewster angle, the reflection will be zero. Thus the transmission is T = 1-R. Since R = 0, T = 1. It is to be noted that T and R lies in the range of 0 to 1.
The reflection coefficient in the wave propagation when it is transmitted with the Brewster angle is
a Explanation: Brewster angle propagation refers to complete transmission. The wave transmitted at the Brewster angle will be completely transmitted without reflection. Thus the reflection coefficient will be zero.
a
See lessExplanation: Brewster angle propagation refers to complete transmission. The wave
transmitted at the Brewster angle will be completely transmitted without reflection. Thus the reflection coefficient will be zero.