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Find the refractive index of a medium having a velocity of 1.5 x 108 .
d Explanation: The refractive index is given by the ratio of the speed of light to the velocity in a particular medium. It is given by n = c/v. On substituting for v = 1.5 x 108 and c = 3 x 108, we get n = 3/1.5 = 2. The quantity has no unit.
d
See lessExplanation: The refractive index is given by the ratio of the speed of light to the velocity in a particular medium. It is given by n = c/v. On substituting for v = 1.5 x 108 and c = 3 x 108, we get n = 3/1.5 = 2. The quantity has no unit.
For total internal reflection to occur, which condition must be satisfied?
b Explanation: The refractive of the transmitting medium should be greater than that of the receiving medium. In other words, the light must flow from denser to rarer medium, for total internal reflection to occur.
b
See lessExplanation: The refractive of the transmitting medium should be greater than that of the
receiving medium. In other words, the light must flow from denser to rarer medium, for
total internal reflection to occur.
Numerical aperture is expressed as the
a Explanation: The numerical aperture is the measure of how much light the fiber can collect. It is the sine of the acceptance angle, the angle at which the light must be transmitted in order to get maximum reflection. Thus it is given by NA = sin θa.
a
See lessExplanation: The numerical aperture is the measure of how much light the fiber can
collect. It is the sine of the acceptance angle, the angle at which the light must be
transmitted in order to get maximum reflection. Thus it is given by NA = sin θa.
The expression for refractive index is given by
b Explanation: The refractive index is defined as the ratio of the velocity of light in a vacuum to its velocity in a specified medium. It is given by n = c/v. It is constant for a particular material.
b
See lessExplanation: The refractive index is defined as the ratio of the velocity of light in a
vacuum to its velocity in a specified medium. It is given by n = c/v. It is constant for a
particular material.
Find the transmission coefficient of a wave, when the return loss is 6 decibel.
a Explanation: The return loss is given by RL = -20log R. The reflection coefficient can be calculated as R = 10(-RL/20), by anti logarithm property. For the given return loss RL = 6, we get R = 10(-6/20) = 0.501. The transmission coefficient will be T = 1 – R = 1-0.501 = 0.498.
a
See lessExplanation: The return loss is given by RL = -20log R. The reflection coefficient can be calculated as R = 10(-RL/20), by anti logarithm property. For the given return loss RL = 6, we get R = 10(-6/20) = 0.501. The transmission coefficient will be T = 1 – R = 1-0.501 = 0.498.
The return loss is given as 12 decibel. Calculate the reflection coefficient.
c Explanation: The return loss is given by RL = -20log R. The reflection coefficient can be calculated as R = 10(-RL/20), by anti logarithm property. For the given return loss RL = 12, we get R = 10(-12/20) = 0.25.
c
See lessExplanation: The return loss is given by RL = -20log R. The reflection coefficient can be calculated as R = 10(-RL/20), by anti logarithm property. For the given return loss RL = 12, we get R = 10(-12/20) = 0.25.
The transmission coefficient is given by 0.65. Find the return loss of the wave.
a Explanation: The transmission coefficient is the reverse of the reflection coefficient, i.e, T+ R = 1. When T = 0.65, we get R = 0.35. Thus the return loss RL = -20log R = -20log 0.35 = 9.11 decibel.
a
See lessExplanation: The transmission coefficient is the reverse of the reflection coefficient, i.e, T+ R = 1. When T = 0.65, we get R = 0.35. Thus the return loss RL = -20log R = -20log 0.35 = 9.11 decibel.
The radiation resistance of an antenna having a power of 120 units and antenna current of 5A is
a Explanation: The power of an antenna is given by Prad = Ia2 Rrad, where Ia is the antenna current and Rrad is the radiation resistance. On substituting the given data, we get Rrad = Prad/Ia2 = 120/52 = 4.8 ohm.
a
See lessExplanation: The power of an antenna is given by Prad = Ia2 Rrad, where Ia is the
antenna current and Rrad is the radiation resistance. On substituting the given data, we get Rrad = Prad/Ia2 = 120/52 = 4.8 ohm.
The reflection coefficient is 0.5. Find the return loss.
c Explanation: The return loss is given by RL = -20log R, where is the reflection coefficient. It is given as 0.5. Thus the return loss will be RL = -20 log 0.5 = 6.02 decibel.
c
See lessExplanation: The return loss is given by RL = -20log R, where is the reflection
coefficient. It is given as 0.5. Thus the return loss will be RL = -20 log 0.5 = 6.02 decibel.
The attenuation is given by 20 units. Find the power loss in decibels.
a Explanation: The attenuation refers to the power loss. Thus the power loss is given by 20 units. The power loss in dB will be 10 log 20 = 13.01 decibel.
a
See lessExplanation: The attenuation refers to the power loss. Thus the power loss is given by
20 units. The power loss in dB will be 10 log 20 = 13.01 decibel.