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The charge density of a electrostatic field is given by
d Explanation: From the Gauss law for electric field, the volume charge density is the divergence of the electric flux density of the field. Thus Div(D) = ρv.
d
See lessExplanation: From the Gauss law for electric field, the volume charge density is the
divergence of the electric flux density of the field. Thus Div(D) = ρv.
Both the conduction and displacement current densities coexist in which medium?
c Explanation: Conduction density exists only for good conductors and displacement density is for dielectrics in any medium at high frequency. Thus both coexist when a conductor is placed in a dielectric medium.
c
See lessExplanation: Conduction density exists only for good conductors and displacement
density is for dielectrics in any medium at high frequency. Thus both coexist when a
conductor is placed in a dielectric medium.
At dc field, the displacement current density will be
a Explanation: The DC field refers to zero frequency. The conduction current is independent of the frequency, whereas the displacement current density is dependent on the frequency, i.e, Jd = jwεE. Thus at DC field, the displacement current density will be zero.
a
See lessExplanation: The DC field refers to zero frequency. The conduction current is
independent of the frequency, whereas the displacement current density is dependent
on the frequency, i.e, Jd = jwεE. Thus at DC field, the displacement current density will be zero.
Find the equation of displacement current density in frequency domain.
a Explanation: The displacement current density is Jd = dD/dt. Since D = εE and in frequency domain d/dt = jw, thus we get Jd = jwεE.
a
See lessExplanation: The displacement current density is Jd = dD/dt. Since D = εE and in
frequency domain d/dt = jw, thus we get Jd = jwεE.
An implication of the continuity equation of conductors is given by
a Explanation: The continuity equation indicates the current density in conductors. This is the product of the conductivity of the conductor and the electric field subjected to it. Thus J = σE is the implication of the continuity equation for conductors.
a
See lessExplanation: The continuity equation indicates the current density in conductors. This is the product of the conductivity of the conductor and the electric field subjected to it. Thus J = σE is the implication of the continuity equation for conductors.
In the conversion of line integral of H into surface integral, which theorem is used?
c Explanation: To convert line integral to surface integral, i.e, in this case from line integral of H to surface integral of J, we use the Stokes theorem. Thus the Maxwell second equation can be written as ∫H.dl = ∫∫J.ds.
c
See lessExplanation: To convert line integral to surface integral, i.e, in this case from line integral of H to surface integral of J, we use the Stokes theorem. Thus the Maxwell second equation can be written as ∫H.dl = ∫∫J.ds.
Calculate the conduction density of a material with resistivity of 0.02 units and electric intensity of 12 units.
b Explanation: The conduction density is given by Jc = σE, where σ is the inverse of resistivity and it is 1/0.02 = 50. Thus we get, Jc = 50 x 12 = 600 units.
b
See lessExplanation: The conduction density is given by Jc = σE, where σ is the inverse of
resistivity and it is 1/0.02 = 50. Thus we get, Jc = 50 x 12 = 600 units.
Find the conduction current density of a material with conductivity 200units and electric field 1.5 units.
d Explanation: The conduction current density is given by Jc = σE, where σ = 200 and E =1.5. Thus we get, Jc = 200 x 1.5 = 300 units.
d
See lessExplanation: The conduction current density is given by Jc = σE, where σ = 200 and E =1.5. Thus we get, Jc = 200 x 1.5 = 300 units.
Find the displacement current density of a material with flux density of 5sin t
c Explanation: The displacement current density is the derivative of the flux density. Thus Jd = dD/dt. Put D = 5sin t in the equation, we get Jd = 5cos t units.
c
See lessExplanation: The displacement current density is the derivative of the flux density. Thus Jd = dD/dt. Put D = 5sin t in the equation, we get Jd = 5cos t units.
In dielectric medium, the Maxwell second equation becomes
a Explanation: In dielectric medium conductivity σ will be zero. So the current density has only the displacement current density. Thus the Maxwell equation will be Curl(H) = Jd.
a
See lessExplanation: In dielectric medium conductivity σ will be zero. So the current density has only the displacement current density. Thus the Maxwell equation will be Curl(H) = Jd.