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prasanjit

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  1. Asked: September 9, 2024In: Education

    The Maxwell second equation that is valid in any conductor is

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:53 pm

    a Explanation: For conductors, the conductivity parameter σ is significant and only the conduction current density exists. Thus the component J = Jc and Curl(H) = Jc.

    a
    Explanation: For conductors, the conductivity parameter σ is significant and only the
    conduction current density exists. Thus the component J = Jc and Curl(H) = Jc.

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      • 0
  2. Asked: September 9, 2024In: Education

    Maxwell second equation is based on which law?

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:53 pm

    a Explanation: The second Maxwell equation is based on Ampere law. It states that the field intensity of a system is same as the current enclosed by it, i.e, Curl(H) = J.

    a
    Explanation: The second Maxwell equation is based on Ampere law. It states that the
    field intensity of a system is same as the current enclosed by it, i.e, Curl(H) = J.

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      • 0
  3. Asked: September 9, 2024In: Education

    To find D from B, sequence followed will be

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:52 pm

    a Explanation: Using Maxwell equation, from B we can calculate E by Curl(E) = -dB /dt. From E, D can be calculated by D = εE. Thus the sequence is B->E->D.

    a
    Explanation: Using Maxwell equation, from B we can calculate E by Curl(E) = -dB /dt.
    From E, D can be calculated by D = εE. Thus the sequence is B->E->D.

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      • 0
  4. Asked: September 9, 2024In: Education

    Calculate the emf of a material having flux density 5sin t in an area of 0.5 units.

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:52 pm

    d Explanation: The emf can be written as Vemf = -d(∫B.ds)/dt. It can be written as Vemf = -B= -5sin t, since the integration and differentiation gets cancelled.

    d
    Explanation: The emf can be written as Vemf = -d(∫B.ds)/dt. It can be written as Vemf = -B= -5sin t, since the integration and differentiation gets cancelled.

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      • 0
  5. Asked: September 9, 2024In: Education

    Calculate the emf of a material having a flux linkage of 2t2 at time t = 1second.

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:51 pm

    b Explanation: The emf of a material is given by Vemf = -dλ/dt. On substituting λ = 2t2 , the emf is 4t. At t = 1 sec, the emf will be 4 units.

    b
    Explanation: The emf of a material is given by Vemf = -dλ/dt. On substituting λ = 2t2
    , the emf is 4t. At t = 1 sec, the emf will be 4 units.

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      • 0
  6. Asked: September 9, 2024In: Education

    When the Maxwell equation is expressed in frequency domain, then which substitution is possible?

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:46 pm

    c Explanation: The conversion of time to frequency domain in Maxwell equation is given by the Fourier Transform. Differentiation in time gives jw in frequency domain. Thus d/dt = jw in frequency domain.

    c
    Explanation: The conversion of time to frequency domain in Maxwell equation is given by the Fourier Transform. Differentiation in time gives jw in frequency domain. Thus d/dt = jw in frequency domain.

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      • 0
  7. Asked: September 9, 2024In: Education

    Which of the following relations holds good?

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:46 pm

    c Explanation: The force of a electrostatic field in given by F = Eq. The force on a conductor is given by F = BIL. In the case when a charge exists on a conductor, both the forces can be equated. Thus Eq = BIL is true.

    c
    Explanation: The force of a electrostatic field in given by F = Eq. The force on a
    conductor is given by F = BIL. In the case when a charge exists on a conductor, both the forces can be equated. Thus Eq = BIL is true.

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      • 0
  8. Asked: September 9, 2024In: Education

    Find the electric field applied on a system with electrons having a velocity 5m/s subjected to a magnetic flux of 3.6 units.

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:45 pm

    b Explanation: The electric field intensity is the product of the velocity and the magnetic flux density. Thus E = v x B, on substituting v = 5 and B = 3.6, we get E = 5 x 3.6 = 18 units.

    b
    Explanation: The electric field intensity is the product of the velocity and the magnetic
    flux density. Thus E = v x B, on substituting v = 5 and B = 3.6, we get E = 5 x 3.6 = 18
    units.

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      • 0
  9. Asked: September 9, 2024In: Education

    Find the Maxwell first law value for the electric field intensity is given by A sin wt az

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:44 pm

    a Explanation: The value of Maxwell first equation is Curl(E). The curl of E is zero. Thus for the given field, the value of Maxwell equation is zero. Thus the field is irrotational. 

    a
    Explanation: The value of Maxwell first equation is Curl(E). The curl of E is zero. Thus for the given field, the value of Maxwell equation is zero. Thus the field is irrotational. 

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      • 0
  10. Asked: September 9, 2024In: Education

    Which of the following identities is always zero for static fields?

    prasanjit
    prasanjit Teacher
    Added an answer on September 10, 2024 at 4:44 pm

    d Explanation: The curl of gradient of a vector is always zero. This is because the gradient of V is E and the curl of E is zero for static fields.

    d
    Explanation: The curl of gradient of a vector is always zero. This is because the gradient of V is E and the curl of E is zero for static fields.

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      • 0
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