Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The magnetic moment and torque are related as follows a)
a Explanation: The torque is defined as the product of the magnetic flux density and the magnetic moment. It is given by T = BM, where M = IA is the magnetic moment.
a
See lessExplanation: The torque is defined as the product of the magnetic flux density and the
magnetic moment. It is given by T = BM, where M = IA is the magnetic moment.
Find the angle at which the torque is minimum.
d Explanation: The torque of a conductor loop is given by T = BIA cos θ. The torque is minimum refers to zero torque. This is possible only when the angle is 90 or perpendicular.
d
See lessExplanation: The torque of a conductor loop is given by T = BIA cos θ. The torque is
minimum refers to zero torque. This is possible only when the angle is 90 or
perpendicular.
The torque of a conductor is defined only in the case when
b Explanation: The torque of a conductor is given by T = NBIA. This equation of the conductor is valid only when the plane of the loop is parallel to the magnetic field applied to it.
b
See lessExplanation: The torque of a conductor is given by T = NBIA. This equation of the
conductor is valid only when the plane of the loop is parallel to the magnetic field applied to it.
Consider the conductor to be a coil of turns 60 and the flux density to be 13.5 units, current 0.12A and area 16units. The torque will be
a Explanation: For a single turn or loop, the torque will be BIA. For N turns, the torque will be T = NBIA, where N = 60, B = 13.5, I = 0.12 and A = 16. Thus T = 60 x 13.5 x 0.12 x 16 = 1555.2 units.
a
See lessExplanation: For a single turn or loop, the torque will be BIA. For N turns, the torque will be T = NBIA, where N = 60, B = 13.5, I = 0.12 and A = 16. Thus T = 60 x 13.5 x 0.12 x 16 = 1555.2 units.
The torque on a conductor with flux density 23 units, current 1.6A and area 6.75 units will be
a Explanation: The maximum torque on a conductor will be at perpendicular angle ie, at 90. The torque will be given as T = BIA, where B = 23, I = 1.6 and A = 6.75.Thus we get, T = 23 x 1.6 x 6.75 = 248.4 units.
a
See lessExplanation: The maximum torque on a conductor will be at perpendicular angle ie, at 90. The torque will be given as T = BIA, where B = 23, I = 1.6 and A = 6.75.Thus we get, T = 23 x 1.6 x 6.75 = 248.4 units.
The distance of the conductor when the area and length of the conductor is 24m2 and 13.56m.
a Explanation: We know that the surface integral is the area component which is the product of two dimensions given by length and distance in a conductor. Thus A = L x d.To get d, d = A/L = 24/13.56 = 1.76 units.
a
See lessExplanation: We know that the surface integral is the area component which is the
product of two dimensions given by length and distance in a conductor. Thus A = L x d.To get d, d = A/L = 24/13.56 = 1.76 units.
Find the torque in a conductor having current 2A, flux density 50 units, length 15cm and distance of 8m.
a Explanation: The torque on a conductor is given by T = BILd, where L x d is the area of the conductor. Thus the torque will be, T = 50 x 2 x 0.15 x 8 = 120 units.
a
See lessExplanation: The torque on a conductor is given by T = BILd, where L x d is the area of the conductor. Thus the torque will be, T = 50 x 2 x 0.15 x 8 = 120 units.
Find the force that exists in an electromagnetic wave.
c Explanation: In an electromagnetic wave, the force of the electric and magnetic field both coexist. This is given by F = qE + q(v x B). It is called Lorentz force.
c
Explanation: In an electromagnetic wave, the force of the electric and magnetic field both coexist. This is given by F = qE + q(v x B). It is called Lorentz force.
See lessThe magnetic force impacts the energy of the field. State True/false.
a Explanation: The magnetic force depends on the flux density of a material and the flux density is in turn dependent on the energy of the material. It can be shown that F = q(v xB) and E = 0.5 x B2/μ. It is clear that B and F are related.
a
See lessExplanation: The magnetic force depends on the flux density of a material and the flux
density is in turn dependent on the energy of the material. It can be shown that F = q(v xB) and E = 0.5 x B2/μ. It is clear that B and F are related.
Find the maximum force of the conductor having length 60cm, current 2.75A and flux density of 9 units.
a Explanation: The force on a conductor is given by F = BIL sin θ, where B = 3.75, I = 8, L= 0.12 and θ = 90 for maximum force. We get F = BIL= 9 x 2.75 x 0.6 sin 90 = 14.85 units.
a
See lessExplanation: The force on a conductor is given by F = BIL sin θ, where B = 3.75, I = 8, L= 0.12 and θ = 90 for maximum force. We get F
= BIL= 9 x 2.75 x 0.6 sin 90 = 14.85 units.