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Which of the following is true regarding magnetic lines of force?
b Explanation: Magnetic Lines of Force is a an imaginary line representing the direction of magnetic field such that the tangent at any point is the direction of the field vector at that point.
b
See lessExplanation: Magnetic Lines of Force is a an imaginary line representing the direction of magnetic field such that the tangent at any point is the direction of the field vector at that point.
Find the magnetization of the field which has a magnetic moment 16 units in a volume of 1.2 units.
b Explanation: The magnetization is the ratio of the magnetic moment to the volume. Thus M = m/v, where m = 16 and v = 1.2. We get M = 16/1.2 = 13.33 units.
b
See lessExplanation: The magnetization is the ratio of the magnetic moment to the volume. Thus M = m/v, where m = 16 and v = 1.2. We get M = 16/1.2 = 13.33 units.
The Bohr magneton is given by
d Explanation: In atomic physics, the Bohr magneton (symbol μB) is a physical constant and the natural unit for expressing the magnetic moment of an electron caused by eitherits orbital or spin angular momentum. It is given by eh/4πm, where h is the Planck’s constant, e is the charge of the electronRead more
d
See lessExplanation: In atomic physics, the Bohr magneton (symbol μB) is a physical constant
and the natural unit for expressing the magnetic moment of an electron caused by eitherits orbital or spin angular momentum. It is given by eh/4πm, where h is the Planck’s constant, e is the charge of the electron and m is the mass of the electron.
Calculate the Larmer angular frequency for a magnetic flux density of 12.34 x 10-10 .
a Explanation: The Larmer angular frequency is the product of magnitude of the ratio of orbital dipole moment to orbital angular moment and the magnetic flux density. It is given by fL = B e/2m, where is the charge of electron and m is the mass of the electron. On substituting, we get fL = 12.34 x 1Read more
a
See lessExplanation: The Larmer angular frequency is the product of magnitude of the ratio of
orbital dipole moment to orbital angular moment and the magnetic flux density. It is given by fL = B e/2m, where is the charge of electron and m is the mass of the electron. On substituting, we get fL = 12.34 x 10-10 x 1.6 x 10-19/(2 x 9.1 x 10-31) = 108.36 units.
The ratio of the orbital dipole moment to the orbital angular moment is given by
d Explanation: The orbital dipole moment is given by M = 0.5 x eVangx r2 and the orbital angular moment is given by Ma = m x Vangx r2. Their ratio M/Ma is given by –e/2m, the negative sign indicates the charge of electron.
d
See lessExplanation: The orbital dipole moment is given by M = 0.5 x eVangx r2 and the orbital angular moment is given by Ma = m x Vangx r2. Their ratio M/Ma is given by –e/2m, the negative sign indicates the charge of electron.
Find the orbital angular moment of a dipole with angular velocity of 1.6m/s and radius 35cm(in 10-31 order)
a Explanation: The orbital angular moment is given by Ma = m x Vangx r2,where m = 9.1 x 10-31, Vang = 1.6 and r = 0.35. On substituting, we get, Ma = 9.1 x 10-31 x 1.6 x 0.352 = 1.78 x 10-31 units.
a
See lessExplanation: The orbital angular moment is given by Ma = m x Vangx r2,where m = 9.1 x 10-31, Vang = 1.6 and r = 0.35. On substituting, we get, Ma = 9.1 x 10-31 x 1.6 x 0.352 = 1.78 x 10-31 units.
Find the orbital dipole moment in a field of dipoles of radius 20cm and angular velocity of 2m/s(in 10-22 order)
a Explanation: The orbital dipole moment is given by M = 0.5 x eVangx r2 , where e = 1.6 x 10-19 is the charge of the electron, Vang = 2 and r = 0.2. On substituting, we get M = 0.5 x 1.6 x 10-19x 2 x 0.22= 64 x 10-22 units.
a
Explanation: The orbital dipole moment is given by M = 0.5 x eVangx r2 , where e = 1.6 x 10-19 is the charge of the electron, Vang = 2 and r = 0.2. On substituting, we get M = 0.5 x 1.6 x 10-19x 2 x 0.22= 64 x 10-22 units.
See lessThe magnetization is defined by the ratio of
b Explanation: The magnetization refers to the amount of dipole formation in a given volume when it is subjected to a magnetic field. It is given by the ratio of the magnetic moment to the volume. Thus Pm = M/V.
b
Explanation: The magnetization refers to the amount of dipole formation in a given volume when it is subjected to a magnetic field. It is given by the ratio of the magnetic moment to the volume. Thus Pm = M/V.
See lessFind the torque of a loop with magnetic moment 12.5 and magnetic flux density 7.65 units is
a Explanation: The torque is defined as the product of the magnetic moment and the magnetic flux density given by T = MB, where M = 12.5 and B = 7.65. Thus we get T = 12.5 x 7.65 = 95.625 units.
a
See lessExplanation: The torque is defined as the product of the magnetic moment and the
magnetic flux density given by T = MB, where M = 12.5 and B = 7.65. Thus we get T =
12.5 x 7.65 = 95.625 units.
The magnetic moment of a field with current 12A and area 1.6 units is
a Explanation: The magnetic moment is the product of current and the area of the conductor. It is given by M = IA, where I = 12 and A = 1.6.Thus we get, M = 12 x 1.6 = 19.2 units.
a
See lessExplanation: The magnetic moment is the product of current and the area of the
conductor. It is given by M = IA, where I = 12 and A = 1.6.Thus we get, M = 12 x 1.6 =
19.2 units.