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Find the magnetic flux density when a flux of 28 units is enclosed in an area of 15cm.
b Explanation: The total flux is the product of the magnetic flux density and the area. Total flux = B x A. To get B, put flux/area. B = 28/0.15 = 186.67 units.
b
See lessExplanation: The total flux is the product of the magnetic flux density and the area. Total flux = B x A. To get B, put flux/area. B = 28/0.15 = 186.67 units.
Find the magnetic flux density of the material with magnetic vector potential A = y i + z j + x k.
b Explanation: The magnetic flux density is the curl of the magnetic vector potential. B =Curl(A). Thus Curl(A) = i(-1) – j(1) + k(-1) = -i – j – k. We get B = -i – j – k.
b
See lessExplanation: The magnetic flux density is the curl of the magnetic vector potential. B =Curl(A). Thus Curl(A) = i(-1) – j(1) + k(-1) = -i – j – k. We get B = -i – j – k.
If ∫ H.dL = 0, then which statement will be true?
c Explanation: The given condition shows that the magnetic field intensity will be the negative gradient of the magnetic vector potential.
c
See lessExplanation: The given condition shows that the magnetic field intensity will be the
negative gradient of the magnetic vector potential.
Find the magnetic field intensity when the flux density is 8 x 10-6 Tesla in the medium of air.
a Explanation: We how that, B = μH. To get H = B/μ, put B = 8 x 10-6 and μ = 4π x 10-7. Thus H = 8 x 10-6 / 4π x 10-7 = 6.36 units.
a
See lessExplanation: We how that, B = μH. To get H = B/μ, put B = 8 x 10-6 and μ = 4π x 10-7. Thus H = 8 x 10-6 / 4π x 10-7 = 6.36 units.
Find the current when the magnetic field intensity is given by 2L and L varies as 0->1.
b Explanation: From Ampere law, we get ∫ H.dL = I. Put H = 2L and L = 0->1. On integrating H with respect to L, the current will be 1A.
b
See lessExplanation: From Ampere law, we get ∫ H.dL = I. Put H = 2L and L = 0->1. On
integrating H with respect to L, the current will be 1A.
Find the flux contained by the material when the flux density is 11.7 Tesla and the area is 2 units.
a Explanation: The total flux is given by φ = ∫ B.ds, where ∫ds is the area. Thus φ = BA. We get φ = 11.7 x 2 = 23.4 units.
a
See lessExplanation: The total flux is given by φ = ∫ B.ds, where ∫ds is the area. Thus φ = BA. We get φ = 11.7 x 2 = 23.4 units.
The divergence of H will be
d Explanation: We know that the divergence of B is zero. Also B = μH. Thus divergence of H is also zero.
d
See lessExplanation: We know that the divergence of B is zero. Also B = μH. Thus divergence of H is also zero.
Identify which of the following is the unit of magnetic flux density?
c Explanation: The unit of magnetic flux density is weber/m2. It is also called as tesla.
c
See lessExplanation: The unit of magnetic flux density is weber/m2. It is also called as tesla.
The magnetic field intensity of an infinite sheet of charge with charge density 36.5 units in air will be
a Explanation: The magnetic field intensity of an infinite sheet of charge is given by H = 0.5 K, for the point above the sheet and –0.5 K, for the point below the sheet. Here k is the charge density. Thus H = 0.5 x 36.5 = 18.25 units.
a
See lessExplanation: The magnetic field intensity of an infinite sheet of charge is given by H =
0.5 K, for the point above the sheet and –0.5 K, for the point below the sheet. Here k is the charge density. Thus H = 0.5 x 36.5 = 18.25 units.
Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A.
a Explanation: The magnetic field intensity of a toroid is given by H = NI/2πrm. Put N = 40, I = 3.25 and rm = 0.2, we get H = 40 x 3.25/2π x 0.2 = 103.45 units.
a
See lessExplanation: The magnetic field intensity of a toroid is given by H = NI/2πrm. Put N = 40, I = 3.25 and rm = 0.2, we get H = 40 x 3.25/2π x 0.2 = 103.45 units.