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Find the magnetic field intensity at the radius of 6cm of a coaxial cable with inner and outer radii are 1.5cm and 4cm respectively. The current flowing is 2A.
c Explanation: The inner radius is 1.5cm and the outer radius is 4cm. It is clear that the magnetic field intensity needs to be calculated outside of the conductor ie, r>4cm. This will lead to zero, since H outside the conductor will be zero.
c
See lessExplanation: The inner radius is 1.5cm and the outer radius is 4cm. It is clear that the
magnetic field intensity needs to be calculated outside of the conductor ie, r>4cm. This will lead to zero, since H outside the conductor will be zero.
Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A.
d Explanation: The magnetic field intensity of a solenoid is given by H = NI/L = 30 X 1.5/0.12 = 375 units.
d
See lessExplanation: The magnetic field intensity of a solenoid is given by H = NI/L = 30 X
1.5/0.12 = 375 units.
Find the height of an infinitely long conductor from point P which is carrying current of 6.28A and field intensity is 0.5 units.
b Explanation: The magnetic field intensity of an infinitely long conductor is given by H =I/2πh. Put I = 6.28 and H = 0.5, we get h = 1/0.5 = 2 units.
b
See lessExplanation: The magnetic field intensity of an infinitely long conductor is given by H =I/2πh. Put I = 6.28 and H = 0.5, we get h = 1/0.5 = 2 units.
Find the electric field when the magnetic field is given by 2sin t in air.
a Explanation: Given H = 2sin t. We get B = μH = 4π x 10-7 x 2sin t = 8πx10-7sin t. To get E, integrate B with respect to time, we get 8πx10-7cos t.
a
See lessExplanation: Given H = 2sin t. We get B = μH = 4π x 10-7 x 2sin t = 8πx10-7sin t.
To get E, integrate B with respect to time, we get 8πx10-7cos t.
Given the magnetic field is 2.4 units. Find the flux density in air(in 10- 6 order).
b Explanation: We know that B = μH. On substituting μ = 4π x 10-7 and H = 2.4, we get B = 4π x 10-7 x 2.4 = 3 x 10-6 units.
b
See lessExplanation: We know that B = μH. On substituting μ = 4π x 10-7 and H = 2.4, we get B = 4π x 10-7 x 2.4 = 3 x 10-6 units.
Ampere law states that,
d Explanation: Ampere circuital law or Ampere law states that the closed integral of the magnetic field intensity is same as the current enclosed by it. It is given by Curl(H) = J.
d
See lessExplanation: Ampere circuital law or Ampere law states that the closed integral of the
magnetic field intensity is same as the current enclosed by it. It is given by Curl(H) = J.
The magnetic flux density is directly proportional to the magnetic field intensity. State True/False.
a Explanation: The magnetic field intensity is directly proportional to the magnetic field intensity for a particular material (Permeability). It is given by B = μH.
a
See lessExplanation: The magnetic field intensity is directly proportional to the magnetic field
intensity for a particular material (Permeability). It is given by B = μH.
The H quantity is analogous to which component in the following?
c Explanation: The H quantity refers to magnetic field intensity in the magnetic field. This is analogous to the electric field intensity E in the electric field.
c
See lessExplanation: The H quantity refers to magnetic field intensity in the magnetic field. This is analogous to the electric field intensity E in the electric field.
Find the electric flux density of a material with charge density 16 units in unit volume.
c Explanation: The electric flux density from Maxwell’s equation is given by D = ∫ ρ dv. On substituting ρ = 16 and ∫dv = 1, we get D = 16 units.
c
See lessExplanation: The electric flux density from Maxwell’s equation is given by D = ∫ ρ
dv. On substituting ρ = 16 and ∫dv = 1, we get D = 16 units.
Find the flux enclosed by a material of flux density 12 units in an area of 80cm.
a Explanation: The total flux in a material is the product of the flux density and the area. It is given by flux = 12 x 0.8= 9.6 units.
a
See lessExplanation: The total flux in a material is the product of the flux density and the area. It is given by flux = 12 x 0.8= 9.6 units.