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Find the current density on the conductor surface when a magnetic field H = 3cos x i + zcos x j A/m, for z>0 and zero, otherwise is applied to a perfectly conducting surface in xy plane.
b Explanation: By Ampere law, Curl (H) = J. The curl of H will be i(-cos x) – j(0) + k(-z sin x) = -cos x i – zsin x k. In the xy plane, z = 0. Thus Curl(H) = J = -cos x i.
b
See lessExplanation: By Ampere law, Curl (H) = J. The curl of H will be i(-cos x) – j(0) + k(-z sin x) = -cos x i – zsin x k. In the xy plane, z = 0. Thus Curl(H) = J = -cos x i.
Find the magnetic field intensity due to an infinite sheet of current 5A and charge density of 12j units in the positive y direction and the z component is below the sheet.
c Explanation: The magnetic intensity when the normal component is below the sheet is Hy = -0.5 K, where K = 12.Thus we get H = -0.5 x 12 = -6 units.
c
See lessExplanation: The magnetic intensity when the normal component is below the sheet is
Hy = -0.5 K, where K = 12.Thus we get H = -0.5 x 12 = -6 units.
Find the magnetic field intensity due to an infinite sheet of current 5A and charge density of 12j units in the positive y direction and the z component is above the sheet.
d Explanation: The magnetic field intensity when the normal component is above the sheet is Hx = 0.5 K, where K = 12. Thus we get H = 0.5 x 12 = 6 units.
d
See lessExplanation: The magnetic field intensity when the normal component is above the sheet is Hx = 0.5 K, where K = 12. Thus we get H = 0.5 x 12 = 6 units.
Calculate the magnetic field intensity due to a toroid of turns 50, current 2A and radius 159mm.
c Explanation: The magnetic field intensity is given by H = NI/2πrm, where N = 50, I = 2A and rm = 1/2π. Thus H = 50 x 2/2π x 0.159 = 100 units.
c
See lessExplanation: The magnetic field intensity is given by H = NI/2πrm, where N = 50, I = 2A
and rm = 1/2π. Thus H = 50 x 2/2π x 0.159 = 100 units.
Find the magnetic flux density of a finite length conductor of radius 12cm and current 3A in air( in 10-6 order)
b Explanation: The magnetic field intensity is given by H = I/2πr, where I = 3A and r = 0.12. The magnetic flux density in air B = μ H, where μ = 4π x 10-7 .Thus B = 4π x 10-7 x 3/2π x 0.12 = 5x 10-6 units.
b
See lessExplanation: The magnetic field intensity is given by H = I/2πr, where I = 3A and r =
0.12. The magnetic flux density in air B = μ H, where μ = 4π x 10-7
.Thus B = 4π x 10-7 x
3/2π x 0.12 = 5x 10-6 units.
Electric field will be maximum outside the conductor and magnetic field will be maximum inside the conductor. State True/False.
a Explanation: At the conductor-free space boundary, electric field will be maximum and magnetic field will be minimum. This implies electric field is zero inside the conductor and increases as the radius increases and the magnetic field is zero outside the conductor and decreases as it approaches tRead more
a
See lessExplanation: At the conductor-free space boundary, electric field will be maximum and
magnetic field will be minimum. This implies electric field is zero inside the conductor
and increases as the radius increases and the magnetic field is zero outside the
conductor and decreases as it approaches the conductor.
The Ampere law is based on which theorem?
c Explanation: The proof of the Ampere’s circuital law is obtained from Stoke’s theorem for H and J only.
c
See lessExplanation: The proof of the Ampere’s circuital law is obtained from Stoke’s
theorem for H and J only.
The point form of Ampere law is given by
d Explanation: Ampere law states that the line integral of H about any closed path is exactly equal to the direct current enclosed by that path. ∫ H.dl = I The point form will be Curl (H) = J.
d
See lessExplanation: Ampere law states that the line integral of H about any closed path is
exactly equal to the direct current enclosed by that path. ∫ H.dl = I The point form will be
Curl (H) = J.
When the conduction current density and displacement current density are same, the dissipation factor will be
d Explanation: Dissipation factor refers to the tangent of loss angle. It is the ratio of conduction current density to displacement current density. When both are same, the loss tangent or the dissipation factor will be unity.
d
See lessExplanation: Dissipation factor refers to the tangent of loss angle. It is the ratio of
conduction current density to displacement current density. When both are same, the
loss tangent or the dissipation factor will be unity.
The time varying electric field E is conservative. State True/False.
b Explanation: The time varying electric field E(t) is not a closed path. Thus the curl will be non-zero. This implies E(t) is not conservative and the statement is false.
b
See lessExplanation: The time varying electric field E(t) is not a closed path. Thus the curl will be
non-zero. This implies E(t) is not conservative and the statement is false.