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Gauss law can be evaluated in which coordinate system?
Answer: d Explanation: The Gauss law exists for all materials. Depending on the Gaussian surface of the material, we take the coordinate systems accordingly. Suppose if the material is a coaxial cable, the Gaussian surface is in the form of cylinder. Thus we take Cylinder/Circular coordinate system.
Answer: d
See lessExplanation: The Gauss law exists for all materials. Depending on the Gaussian surface of the material, we take the coordinate systems accordingly. Suppose if the material is a coaxial cable, the Gaussian surface is in the form of cylinder. Thus we take Cylinder/Circular coordinate system.
Three charged cylindrical sheets are present in three spaces with σ = 5 at R = 2m, σ = -2 at R = 4m and σ = -3 at R = 5m. Find the flux density at R = 6m.
Answer: d Explanation: The radius R = 6m encloses all the three Gaussian cylinders. By Gauss law, ψ = Q D(2πRL) = σ(2πRL), D(2π X 6) = Q1 + Q2 + Q3 = σ1(2π X 2) + σ2(2π X 4) + σ3(2π X 5), here σ1 = 5, σ2 = -2 and σ3 = -3. We get D = -13/6 units.
Answer: d
Explanation: The radius R = 6m encloses all the three Gaussian cylinders.
By Gauss law, ψ = Q
D(2πRL) = σ(2πRL), D(2π X 6) = Q1 + Q2 + Q3 = σ1(2π X 2) + σ2(2π X 4) + σ3(2π X
See less5), here σ1 = 5, σ2 = -2 and σ3 = -3. We get D = -13/6 units.
Three charged cylindrical sheets are present in three spaces with σ = 5 at R = 2m, σ = -2 at R = 4m and σ =-3 at R = 5m. Find the flux density at R = 4.5m.
Answer: c Explanation: The Gaussian cylinder of R = 4.5m encloses sum of charges of two cylinders (R = 2m and R = 4m). By Gauss law, ψ = Q D(2πRL) = σ(2πRL), D(2π X 4.5) = Q1 + Q2 = σ1(2π X 2) + σ2(2π X 4), here σ1 = 5 and σ2 = -2. We get D = 2/4.5 units.
Answer: c
Explanation: The Gaussian cylinder of R = 4.5m encloses sum of charges of two
cylinders (R = 2m and R = 4m).
By Gauss law, ψ = Q
See lessD(2πRL) = σ(2πRL), D(2π X 4.5) = Q1 + Q2 = σ1(2π X 2) + σ2(2π X 4), here σ1 = 5
and σ2 = -2. We get D = 2/4.5 units.
Three charged cylindrical sheets are present in three spaces with σ = 5 at R = 2m, σ = -2 at R = 4m and σ = -3 at R = 5m. Find the flux density at R = 3m.
Answer: b Explanation: The radius is 3m, hence it will enclose one Gaussian cylinder of R = 2m. By Gauss law, ψ = Q D(2πRL) = σ(2πRL), D(2π X 3) = σ(2π X 2), Thus D = 10/3 units.
Answer: b
See lessExplanation: The radius is 3m, hence it will enclose one Gaussian cylinder of R = 2m.
By Gauss law, ψ = Q
D(2πRL) = σ(2πRL), D(2π X 3) = σ(2π X 2), Thus D = 10/3 units.
Three charged cylindrical sheets are present in three spaces with σ = 5 at R = 2m, σ = -2 at R = 4m and σ = -3 at R = 5m. Find the flux density at R = 1m.
Answer: a Explanation: Since 1m does not enclose any cylinder (three Gaussian surfaces of radius 2m, 4m, 5m exists), the charge density and charge becomes zero according to Gauss law. Thus flux density is also zero.
Answer: a
See lessExplanation: Since 1m does not enclose any cylinder (three Gaussian surfaces of
radius 2m, 4m, 5m exists), the charge density and charge becomes zero according
to Gauss law. Thus flux density is also zero.
Gauss law can be used to compute which of the following?
Answer: c Explanation: Gauss law relates the electric flux density and the charge density. Thus it can be used to compute radius of the Gaussian surface. Permittivity and permeability are constants for a particular material.
Answer: c
See lessExplanation: Gauss law relates the electric flux density and the charge density. Thus it
can be used to compute radius of the Gaussian surface. Permittivity and permeability
are constants for a particular material.
Gauss law for magnetic fields is given by
Answer: b Explanation: The divergence of magnetic flux density is always zero. This is called Gauss law for magnetic fields. It implies the non-existence of magnetic monopoles in any magnetic field.
Answer: b
See lessExplanation: The divergence of magnetic flux density is always zero. This is called
Gauss law for magnetic fields. It implies the non-existence of magnetic monopoles in
any magnetic field.
Gauss law cannot be used to find which of the following quantity?
Answer: d Explanation: Permittivity is constant for a particular material(say permittivity of water is 1). It cannot be determined from Gauss law, whereas the remaining options can be computed from Gauss law.
Answer: d
See lessExplanation: Permittivity is constant for a particular material(say permittivity of water is
1). It cannot be determined from Gauss law, whereas the remaining options can be
computed from Gauss law.
Find the potential due to a charged ring of density 2 units with radius 2m and the point at which potential is measured is at a distance of 1m from the ring.
Answer: d Explanation: The potential due to a charged ring is given by λa/2εr, where a = 2m and r = 1m. We get V = 72π volts.
Answer: d
See lessExplanation: The potential due to a charged ring is given by λa/2εr, where a = 2m and r = 1m. We get V = 72π volts.
The potential of a coaxial cylinder with charge density 1 unit , inner radius 1m and outer cylinder 2m is (in 109 )
Answer: c Explanation: The potential of a coaxial cylinder will be ρl ln(b/a)/2πε, where ρl = 1, b =2m and a = 1m. We get V = 12.47 X 109 volts.
Answer: c
See lessExplanation: The potential of a coaxial cylinder will be ρl ln(b/a)/2πε, where ρl = 1, b =2m and a = 1m. We get V = 12.47 X 109 volts.