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The work done by a charge of 10μC with a potential 4.386 is (in μJ)
Answer: b Explanation: By Gauss law principles, W = Q X V = 10 X 10-6 X 4.386 = 43.86 X 10- 6 joule.
Answer: b
See lessExplanation: By Gauss law principles, W = Q X V = 10 X 10-6 X 4.386 = 43.86 X 10-
6 joule.
The total charge of a surface with densities 1,2,…,10 is
Answer: c Explanation: Q = ∫∫D.ds. Since the data is discrete, the total charge will be summation of 1,2,…,10,i.e, 1+2+…+10 = 10(11)/2 = 55.
Answer: c
Explanation: Q = ∫∫D.ds. Since the data is discrete, the total charge will be summation of 1,2,…,10,i.e, 1+2+…+10 = 10(11)/2 = 55.
See lessA circular disc of radius 5m with a surface charge density ρs = 10sinφ is enclosed by surface. What is the net flux crossing the surface?
Answer: d Explanation: Q = ∫ ρsds = ∫∫ 10sinφ rdrdφ, on integrating with r = 0->5 and φ = 0->2π, we get Q = ψ = 0.
Answer: d
See lessExplanation: Q = ∫ ρsds = ∫∫ 10sinφ rdrdφ, on integrating with r = 0->5 and φ = 0->2π, we get Q = ψ = 0.
The Gaussian surface for a point charge will be
Answer: c Explanation: A point charge is single dimensional. The three dimensional imaginary enclosed surface of a point charge will be sphere.
Answer: c
See lessExplanation: A point charge is single dimensional. The three dimensional imaginary
enclosed surface of a point charge will be sphere.
The Gaussian surface for a line charge will be
Answer: b Explanation: A line charge can be visualized as a rod of electric charges. The three dimensional imaginary enclosed surface of a rod can be a cylinder.
Answer: b
See lessExplanation: A line charge can be visualized as a rod of electric charges. The three
dimensional imaginary enclosed surface of a rod can be a cylinder.
Divergence theorem is based on
Answer: a Explanation: The divergence theorem relates surface integral and volume integral. Div(D) = ρv, which is Gauss’s law.
Answer: a
See lessExplanation: The divergence theorem relates surface integral and volume integral.
Div(D) = ρv, which is Gauss’s law.
The voltage at any point in an ac circuit will be
Answer: b Explanation: In any ac circuit, the voltage measured will not be exact maximum. In order to normalise, we assume the instantaneous voltage at any point be 70.7% of the peak value, which is called the root mean square (RMS)voltage.
Answer: b
See lessExplanation: In any ac circuit, the voltage measured will not be exact maximum. In order to normalise, we assume the instantaneous voltage at any point be 70.7% of the peak value, which is called the root mean square (RMS)voltage.
What is the potential difference between 10sinθcosφ/r 2 at A(1,30,20) and B(4,90,60)?
Answer: c Explanation: Potential at A, Va = 10sin30cos20/12 = 4.6985 and Potential at B, Vb = 10sin90cos60/42 = 0.3125. Potential difference between A and B is, Vab = 4.6985 – 0.3125 = 4.386 volts.
Answer: c
See lessExplanation: Potential at A, Va = 10sin30cos20/12 = 4.6985 and Potential at B, Vb =
10sin90cos60/42 = 0.3125. Potential difference between A and B is, Vab = 4.6985 –
0.3125 = 4.386 volts.
The potential taken between two points across a resistor will be
Answer: b Explanation: The resistor will absorb power and dissipate it in the form of heat energy.The potential between two points across a resistor will be negative.
Answer: b
See lessExplanation: The resistor will absorb power and dissipate it in the form of heat energy.The potential between two points across a resistor will be negative.
The potential difference in an open circuit is
Answer: c Explanation: In an open circuit no current exists due to non-existence of loops. Also voltage/potential will be infinity in an open circuit.
Answer: c
See lessExplanation: In an open circuit no current exists due to non-existence of loops. Also
voltage/potential will be infinity in an open circuit.