Home/ Questions/Q 1035058
Next
In Process

Quearn Latest Questions

junaid ansari
  • -2
  • -2
Poll
Asked: 2024-08-30T23:20:21+05:30 In:

A 200 bus power system has 160 PQ bus. For achieving a load flow solution by N-R in polar coordinates, the minimum number of simultaneous equation to be solved is ___________

  • -2
  • -2

Poll Results

33.33%a) 359 ( 1 voter )
0%b) 334 ( 0 voters )
33.33%c) 357 ( 1 voter )
33.33%d) 345 ( 1 voter )
Based On 3 Votes

Participate in Poll, Choose Your Answer.

solution

    You must login to add an answer.

    Need An Account,

    1 Answer

    1. junaid ansari

      a
      Explanation: Total buses = 200
      PQ buses = 160
      PV buses = 200-160 = 40
      Slack bus = 1
      Total number of equation = (40-1)*1 + (160*2) = 359.

        • 0