A current commutated chopper is fed from a source of 230 V. Its commutating components are L = 20 μH and C = 50 μF. Find the value of peak commutating current

To find the peak commutating current in a current commutated chopper circuit, we can use the formula derived from the relationships between the inductor (L), capacitor (C), and the applied voltage (V).

The peak commutating current (I_peak) can be calculated using the following formula:

[

I_{peak} = sqrt{frac{V^2}{frac{L}{C}}}

]

Given:

– V = 230 V

– L = 20 μH = 20 x 10^{-6} H

– C = 50 μF = 50 x 10^{-6} F

Now, substituting the values into the formula:

1. Calculate (frac{L}{C}):

[

frac{L}{C} = frac{20 times 10^{-6}}{50 times 10^{-6}} = frac{20}{50} = 0.4 text{ seconds}

]

2. Substitute into the equation for I_peak:

[

I_{peak} = sqrt{frac{230^2}{0.4}} = sqrt{frac{52900}{0.4}} = sqrt{132250} approx 363.42 text{ A}

]

Therefore, the peak commutating current is approximately 363.42 A.