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Answer: d
Explanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9)/(4πε x 1) = 18 volts.
To calculate the electric potential ( V ) at a point in space due to a point charge, we can use the formula:
[
V = frac{k cdot Q}{r}
]
Where:
– ( V ) is the electric potential,
– ( k ) is Coulomb’s constant, approximately ( 8.99 times 10^9 , text{N m}^2/text{C}^2 ),
– ( Q ) is the charge (in coulombs),
– ( r ) is the distance from the charge to the point where the potential is being calculated (in meters).
In this case:
– The point charge ( Q = 2 , text{nC} = 2 times 10^{-9} , text{C} ).
– The point where we want to calculate the potential is at ( (1,0,0) ) meters, which is 1 meter away from the origin where the charge is located.
Now, substituting the values into the formula:
1. Calculate ( r ):
[
r = 1 , text{m}
]
2. Substitute ( k ), ( Q ), and ( r ) into the formula:
[
V = frac{(8.99 times 10^9) cdot (2 times 10^{-9})}{