A single phase full bridge inverter has load R = 2 Ω, and dc voltage source Vs = 230 V. Find the rms value of the fundamental load current.

To find the rms value of the fundamental load current in a single-phase full bridge inverter, we can use the formula for the maximum output current, which is given by:

[ I_{text{max}} = frac{V_s}{R} ]

where:

– ( V_s ) is the DC voltage source,

– ( R ) is the load resistance.

Given:

– ( V_s = 230 , V )

– ( R = 2 , Omega )

First, we calculate ( I_{text{max}} ):

[

I_{text{max}} = frac{230 , V}{2 , Omega} = 115 , A

]

The rms value of the fundamental load current for a full bridge inverter is given by:

[

I_{rms} = frac{I_{text{max}}}{sqrt{2}} approx frac{115 , A}{sqrt{2}} approx 81.02 , A

]

Thus, the rms value of the fundamental load current is approximately:

81.02 A