A single phase full bridge inverter using transistors and diodes is feeding a R load of 3 Ω with the dc input voltage of 60 V. Find the fundamental frequency output power.

To find the fundamental frequency output power of a single-phase full bridge inverter feeding a resistive load (R load) of 3 Ω with a DC input voltage of 60 V, we can use the following formula for power:

[

P = frac{V_{rms}^2}{R}

]

Where:

– ( V_{rms} ) is the root mean square voltage across the load.

For a full bridge inverter, the output voltage waveform is a square wave. The RMS value of a square wave is equal to the peak value divided by √2.

1. Calculate the peak output voltage: The peak output voltage (V_peak) is equal to the input DC voltage (V_dc), which is 60 V.

2. Calculate the RMS voltage:

[

V_{rms} = frac{V_{peak}}{sqrt{2}} = frac{60 V}{sqrt{2}} approx 42.43 V

]

3. Now, calculate the output power:

[

P = frac{V_{rms}^2}{R} = frac{(42.43 V)^2}{3 , Omega} approx frac{1805.64}{3} approx 601.88 W

]

Thus, the fundamental frequency output power is approximately 601.88 W.