A three-phase full converter charges a battery from a three-phase supply of 230 V. The battery emf is 200 V and the internal resistance of the battery is 0.5 Ω. Find the value of the continuous current which is flowing through the battery if its terminal voltage is 210 V

To find the continuous current flowing through the battery, we can use Ohm’s law and the formula for the terminal voltage of the battery.

Given:

– Battery emf (E = 200 , V)

– Internal resistance (r = 0.5 , Omega)

– Terminal voltage (V = 210 , V)

The terminal voltage can be expressed as:

[

V = E + I cdot r

]

Where (I) is the current flowing through the battery.

Rearranging the formula to find the current (I):

[

I = frac{V – E}{r}

]

Substituting in the known values:

[

I = frac{210 , V – 200 , V}{0.5 , Omega}

]

[

I = frac{10 , V}{0.5 , Omega} = 20 , A

]

Thus, the continuous current flowing through the battery is 20 A.