A type A step down chopper has Vs = 220 V and is connected to RLE load. With R = 1 Ω, E = 24 V and L large enough to maintain continuous conduction. Find the average value of load current for a duty cycle of 30 %.

To find the average value of the load current ( I_{avg} ) in a type A step-down chopper circuit, we can use the formula:

[

I_{avg} = frac{D cdot Vs}{R} – frac{D cdot E}{R}

]

Where:

– ( D ) is the duty cycle (as a decimal),

– ( Vs ) is the supply voltage,

– ( R ) is the load resistance,

– ( E ) is the back EMF from the load.

Given:

– ( Vs = 220 , V )

– ( D = 0.30 ) (30%)

– ( R = 1 , Omega )

– ( E = 24 , V )

Now, substituting the values into the formula:

[

I_{avg} = frac{0.30 cdot 220}{1} – frac{0.30 cdot 24}{1}

]

Calculating each part:

1. ( 0.30 cdot 220 = 66 , V )
2. ( 0.30 cdot 24 = 7.2 , V )

Now, substituting these results back into the equation:

[

I_{avg} = 66 – 7.2 = 58.8 , A

]

Therefore, the average value of