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Home/ Questions/Q 1031354
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rohit
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rohitBegginer
Asked: August 27, 20242024-08-27T16:24:36+05:30 2024-08-27T16:24:36+05:30In: Education

A uniform surface charge of σ = 2 μC/m2 , is situated at z = 2 plane. What is the value of flux density at P(1,1,1)m?

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      Quearn Quearnist
      2024-08-27T16:24:40+05:30Added an answer on August 27, 2024 at 4:24 pm

      To find the electric flux density ( mathbf{D} ) due to a uniform surface charge density ( sigma ) located in the plane ( z = 2 ), we can use Gauss’s law.

      The electric flux density ( mathbf{D} ) near an infinite plane sheet of charge is given by:

      [

      mathbf{D} = frac{sigma}{2} hat{n}

      ]

      where ( hat{n} ) is the unit normal vector pointing away from the surface. The surface charge density ( sigma = 2 , mu C/m^2 = 2 times 10^{-6} , C/m^2 ).

      The normal vector ( hat{n} ) points in the positive ( z )-direction since the sheet is placed at ( z = 2 ) and we are considering points above the sheet.

      Calculating the flux density ( mathbf{D} ):

      [

      mathbf{D} = frac{2 times 10^{-6} , C/m^2}{2} hat{k} = 10^{-6} , C/m^2 hat{k}

      ]

      Since the point ( P(1, 1, 1) ) is below the plane at ( z = 2 ), we should consider the contribution of the plane charge in the ( z = 1 ) direction (down

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    2. prasanjit
      prasanjit Teacher
      2024-09-21T17:00:09+05:30Added an answer on September 21, 2024 at 5:00 pm

      Answer: b
      Explanation: The flux density of any field is independent of the position (point). D = σ/2 =2 X 10-6(-az)/2 = -10-6.

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