Calculate the electric field when the conductivity is 20 units, electron density is 2.4 units and the velocity is 10m/s. Assume the conduction and convection current densities are same

The electric field (E) in a conductor, where the conduction and convection current densities are considered equal, can be described in terms of the conductivity ((sigma)), electron density ((n)), and electron drift velocity ((v_d)) using Ohm’s Law and the definition of current density.

Ohm’s Law in terms of current density ((J)) and electric field ((E)) is given as:

[J = sigma E]

The current density can also be related to the electron charge ((e)), electron density ((n)), and electron drift velocity ((v_d)) as:

[J = n e v_d]

Given that the conduction and convection current densities are the same, we set these two expressions for (J) equal to each other:

[n e v_d = sigma E]

Rearranging this equation to solve for (E) gives:

[E = frac{n e v_d}{sigma}]

However, to compute the value of (E), we need the value of the electron charge ((e)). The charge of an electron is a constant, approximately equal to (1.6 times 10^{-19} , C) (Coulombs).

Given:

– Conductivity, (sigma = 20 , text{units}) (assuming SI units, (text{S/m}))

–