jangyasinniTeacher

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To calculate the polarization vector ( vec{P} ) in a medium such as air, when given the electric susceptibility ( chi_e ) and the electric field ( vec{E} ), you can use the relation:

[ vec{P} = epsilon_0 chi_e vec{E} ]

where

– ( vec{P} ) is the polarization vector,

– ( epsilon_0 ) is the permittivity of free space ((8.854 times 10^{-12} , text{F/m})),

– ( chi_e ) is the electric susceptibility,

– ( vec{E} ) is the electric field.

Given:

– Electric susceptibility, ( chi_e = 5 ),

– Electric field, ( vec{E} = 12 , text{units} ).

Substitute the given values to calculate ( vec{P} ):

[ vec{P} = (8.854 times 10^{-12} , text{F/m}) cdot 5 cdot 12 , text{units} ]

[ = 442.7 times 10^{-12} , text{units} ]

[ = 4.427 times 10^{-10} , text{units} ]

Therefore, the polarization vector ( vec{P}

c

Explanation: The polarisation vector is given by, P = ε0 x χe x E, where χe = 5 and ε0 =

12. On substituting, we get P = 1 x 5 x 12 = 60 units.

c) 60

Explanation: The polarisation vector is given by, P = ε0 x χe x E, where χe = 5 and ε0 =12. On substituting, we get P = 1 x 5 x 12 = 60 units.