jangyasinniTeacher
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To compute the loss factor when given the loss tangent and the real part of the dielectric constant, you can use the following relation:
[ text{Loss Factor} = tan(delta) times epsilon’ ]
Where:
– ( tan(delta) ) is the loss tangent (given as 0.88 in this case),
– ( epsilon’ ) is the real part of the dielectric constant (given as 24 in this case).
Substituting the given values:
[ text{Loss Factor} = 0.88 times 24 = 21.12 ]
Therefore, the loss factor is 21.12.
d
Explanation: The loss factor is nothing but the imaginary part of AC dielectric. It is given
by, ε“ = ε` tan δ. We get loss factor as 24 x 0.88 = 21.12.
d
Explanation: The loss factor is nothing but the imaginary part of AC dielectric. It is given by, ε“ = ε` tan δ. We get loss factor as 24 x 0.88 = 21.12.