jangyasinniTeacher

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

To compute the loss factor when given the loss tangent and the real part of the dielectric constant, you can use the following relation:

[ text{Loss Factor} = tan(delta) times epsilon’ ]

Where:

– ( tan(delta) ) is the loss tangent (given as 0.88 in this case),

– ( epsilon’ ) is the real part of the dielectric constant (given as 24 in this case).

Substituting the given values:

[ text{Loss Factor} = 0.88 times 24 = 21.12 ]

Therefore, the loss factor is 21.12.

d

Explanation: The loss factor is nothing but the imaginary part of AC dielectric. It is given

by, ε“ = ε` tan δ. We get loss factor as 24 x 0.88 = 21.12.

d

Explanation: The loss factor is nothing but the imaginary part of AC dielectric. It is given by, ε“ = ε` tan δ. We get loss factor as 24 x 0.88 = 21.12.